cout<<"Give me your month money"<<endl;
cin >> monthmoney;
cout << "Do you want to purchase something? Y/N" << endl;
cin >> a;
if (a==y)
{
cout << "Type the amount you want to spend";
cin >> usedmoney;
monthmoney-=usedmoney;
cout << monthmoney;
}
else
{
cout << "Goodbye";
}
return 0;
}
The program runs but when i type y (i want to make a purchase ) it just goes to the else statement:
[Switching to process 1808]
Running…
Give me your month money
700
Do you want to purchase something? Y/N
y
Goodbye
Debugger stopped.
Program exited with status value:0.
I modified the program like this to see if the problem was the characters and it worked :
cout << "Do you want to purchase something? Y=1/N=2" << endl;
cin >> a;
if (a==1) {...........}
But i want the user to give me Y/N not a number can someone post the solution please?
Thanks
I don´t know why y/n are 1/2.. But you should do if(y=='y') //note the '' around y
When you use a==1 it's a good expression, since you don't need to use the '' there...
Just remember: for char evaluations, use ", for numeric evaluations don't..