Function does not take 0 arguments

[James5955]

Hello, I'm very new to C++ programming and I'm trying to get this script to work and the only error that I'm getting is:

Function does not take 0 arguments

I've googled this error to attempt to learn from other programmers mistakes, but after looking at several examples I still can't seem to find out what's wrong with my coding. It would be greatly appreciated if someone could take a look at it and get back to me on what I did wrong:

#include <stdio.h>
#include <cstdio>
#include <math.h>
#include <iostream>

float problem2a(float x, float y)
{

	printf("Please enter two floating point values: ");
	scanf("%f %f", x, y);
	printf("The two floating point values you have entered are: ");
	printf("%f and ", x);
	printf("%f\n", y);

	printf("%f ", x); 
	printf("and %f", y);
	printf("are multiplied together the result is: %f", x * y);

	return x * y;

}

float main()
{
	problem2a();
}

I believe it has to do with the bolded/underlined section, but I'm not quite sure on how to fix this error. Any help is appreciated, thanks.

[Albatross]

main() cannot be of type float. It's not legal, and you should change it to int. :(

I'd make problem2a not take any arguments (get rid of the underlined part) and just declare your variables inside the function normally: float x, y;

-Albatross

[James5955]

Excellent thank you for the quick response, I fixed that part and now my code looks like this:

float problem2a()
{
	float x, y;
	float result = x * y;
	
	printf("Please enter two floating point values: ");
	scanf("%f %f", x, y);
	printf("The two floating point values you have entered are: ");
	printf("%f and ", x);
	printf("%f\n", y);

	printf("%f ", x); 
	printf("and %f", y);
	printf("are multiplied together the result is: %f", result);

	return result;

}

int main()
{
	problem2a();
}

Though when I run the program I get a run time error that says:

The variable "x" is being used without being initialized

I thought I initialized it when I put

float x;

in the function, but I guess I'm wrong >.<

Thanks again for the help.

[Galik]

You are trying to multiply x and y before you have given them any values. Try moving your multiply instruction after you have accepted values for x and y. You can't multiply something that you don't have...

[Galik]

Computer programs are not mathematical equations. They are lists of instructions to be obeyed in strict order. ;o)

[James5955]

Makes sense, anyways it works now:

float problem2a()
{
	float x;
	float y;
	
	printf("Please enter two floating point values: ");
	scanf("%f ", &x);
	scanf("%f ", &y);

	float result = x * y;

	printf("The two floating point values you have entered are: \n");
	printf("%f and ", x);
	printf("%f\n", y);

	printf("%f ", x); 
	printf("and %f", y);
	printf("are multiplied together the result is: %f", result);

	return result;

}

int main()
{
	problem2a();
}

Not only did I switch the placement of the x * y = result portion of the code, but I put & in front of x and y when it goes to scan. Works like a charm now, thanks a lot!

And yes, a very strict order as I'm learning xD