Can you explain me please what the problem here is and give me an example if its possible!!
#include <iostream>
#include <cmath>
using namespace std;
int main()
{
using namespace std;
double persons(10);
int max,min;
max=0;
int k;
int i;
int g;
for (i=0;i<10;i++)
{
cout<< "give me number of pancakes for person number:" << (i+1);
cin<< persons(i);
min=persons(0);
if (persons(i) > max)
{
max = persons(i);
}
else if (persons(i) < min)
{
min = persons(i);
k = i;
}
}
cout<< "Person number:" << k << "ate least number of pancakes.";
for (g=0;g<10;g++)
{
cout << "Person number " << (g+1) << "ate" << persons(g) << "pancakes";
}
return 0;
}
double persons(10);
No. persons is a variable, not a function. I think you meant to use [] instead of ().
could you please post the correct program because i've read the tutorials and i cant work it out.
double persons[10];
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Indeed, when there's a "persons" and (something) after it, replace ( with [ and ) with ].
-Albatross
ok changed it like this and now only 1 error occurs:
#include <iostream>
#include <cmath>
using namespace std;
int main()
{
using namespace std;
double persons[10];
int max,min;
max=0;
int k;
int i;
int g;
for (i=0;i<10;i++)
{
cout<< "give me number of pancakes for person number:" << (i+1);
cin<< persons[(i)]; <--Here is the problem now " not math for operator" error
min=persons[(0)];
if (persons[(i)] > max)
{
max = persons[(i)];
}
else if (persons[(i)] < min)
{
min = persons[(i)];
k = i;
}
First of all, you can just do [i] and not [(i)].
The error is because you're using cin wrong. It should be >> and not <<.
Last edited on