undeclared identifier/uninitialized local variable
I have read and reread the chapter(s). I have used every thing I can think of (limited I admit) and all I seem do is change the error message from undeclared identifier to uninitialized local variable and back again. I know this is ugly and it probably doesn't work (once I get past this) but it is set up the way our instructor wants,
Any and all suggestions, remarks, assumptions, etc will be accepted with grace in the hopes that I will learn this (sooner rather than later) but this has given me a huge brain fart and all I do is keep looping the same conclusions over and over
Anyway. I am attempting to have the user enter a number and have the program return a roman numeral. I have tried char with several different names = "I" etc. and I have done "I" = several different names as well as int with variations and still it eludes me.
Code:
#include <iostream>
#include <iomanip>
#include <cstdlib>
using namespace std;
int main()
{ //this is were it all has fallen apart the following line. char gets me undeclared identifier and int is an undeclared local variable (when I change the variables in the other lines)
char a=I, b=II, c=III, d=IV, e=V, f=VI, g=VII, h=VIII, i=IX, j=X;
double num1 =0, num2=0, num3=0, num4=0, num5=0, num6=0, num7=0, num8=0, num9=0, num10=0,
number;
//I don't know if anything after works but I need to get there to work it. Any help to get beyond this point will be accepted and appreciated.
cout << "Please enter a number between one and ten. " << endl;
cin >> number;
if (number == num1)
{
cout << " The Roman Numeral for your number is: " << a << endl;
}
if (number == num2)
{
cout << " The Roman Numeral for your number is: " << b << endl;
}
if (number == num3)
{
cout << " The Roman Numeral for your number is: " << c << endl;
}
if (number == num4)
{
cout << " The Roman Numeral for your number is: " << d << endl;
}
if (number == num5)
{
cout << " The Roman Numeral for your number is: " << e << endl;
}
if (number == num6)
{
cout << " The Roman Numeral for your number is: " << f << endl;
}
if (number == num7)
{
cout << " The Roman Numeral for your number is: " << g << endl;
}
if (number == num8)
{
cout << " The Roman Numeral for your number is: " << h << endl;
}
if (number == num9)
{
cout << " The Roman Numeral for your number is: " << i << endl;
}
if (number == num10)
{
cout << " The Roman Numeral for your number is: " << j << endl;
}
else if (number <1 || >10);
{
cout << "Your number is incorrect " << num1 << endl;
}
return 0;
}
Maybe I can get down this end to see if it will work. Hey anythings possible!
Thanks for the time and trouble.
Kelly
Any and all suggestions, remarks, assumptions, etc will be accepted with grace in the hopes that I will learn this (sooner rather than later) but this has given me a huge brain fart and all I do is keep looping the same conclusions over and over
Anyway. I am attempting to have the user enter a number and have the program return a roman numeral. I have tried char with several different names = "I" etc. and I have done "I" = several different names as well as int with variations and still it eludes me.
Code:
#include <iostream>
#include <iomanip>
#include <cstdlib>
using namespace std;
int main()
{ //this is were it all has fallen apart the following line. char gets me undeclared identifier and int is an undeclared local variable (when I change the variables in the other lines)
char a=I, b=II, c=III, d=IV, e=V, f=VI, g=VII, h=VIII, i=IX, j=X;
double num1 =0, num2=0, num3=0, num4=0, num5=0, num6=0, num7=0, num8=0, num9=0, num10=0,
number;
//I don't know if anything after works but I need to get there to work it. Any help to get beyond this point will be accepted and appreciated.
cout << "Please enter a number between one and ten. " << endl;
cin >> number;
if (number == num1)
{
cout << " The Roman Numeral for your number is: " << a << endl;
}
if (number == num2)
{
cout << " The Roman Numeral for your number is: " << b << endl;
}
if (number == num3)
{
cout << " The Roman Numeral for your number is: " << c << endl;
}
if (number == num4)
{
cout << " The Roman Numeral for your number is: " << d << endl;
}
if (number == num5)
{
cout << " The Roman Numeral for your number is: " << e << endl;
}
if (number == num6)
{
cout << " The Roman Numeral for your number is: " << f << endl;
}
if (number == num7)
{
cout << " The Roman Numeral for your number is: " << g << endl;
}
if (number == num8)
{
cout << " The Roman Numeral for your number is: " << h << endl;
}
if (number == num9)
{
cout << " The Roman Numeral for your number is: " << i << endl;
}
if (number == num10)
{
cout << " The Roman Numeral for your number is: " << j << endl;
}
else if (number <1 || >10);
{
cout << "Your number is incorrect " << num1 << endl;
}
return 0;
}
Maybe I can get down this end to see if it will work. Hey anythings possible!
Thanks for the time and trouble.
Kelly
When you say something like:
You are making the variable 'a' be equal to the variable 'I'. Since you have no variable 'I', etc., you are getting errors. You probably wanted to create a character literal, like so:
However you should note that a character is only one character. So "II" cannot be a character.
char a = I;You are making the variable 'a' be equal to the variable 'I'. Since you have no variable 'I', etc., you are getting errors. You probably wanted to create a character literal, like so:
char a = 'I';However you should note that a character is only one character. So "II" cannot be a character.
Thank You for your help. My instructor went over everything again this AM since I wasn't the only one emailing him. I really appreciate the effort and I'm sure I'll be back.
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