Two switch statements in one?

[kielmaru]

We were given a problem like this:
Compute for the total tuition fee of a student based on the course given.
Year Level Description Course Rate
1 Freshman BSIT 225.40
2 Sophomore BS-CS 423.42
3 Junior Mgt 234
4 Senior Finance 425.31

Input no. of units, downpayment, and year level. Ouput total tuition fee, balance, and description of year level.

Here's what I did:

#include <iostream>
#include <string>
using namespace std;
int main ()

{
     int units, yc, cc;
     double dp, ttf, bal;
     
     cout <<"Enter no. of units:";
     cin >> units;
     
     cout <<"Enter your downpayment:";
     cin >> dp;
     
     cout <<"Enter your year level:";
     cin >> yc;
     
     cout <<"Enter your course:";
     cin >> cc;
     
     switch (yc)
     {
            case 1: cout <<"Freshman";
            break;
            case 2: cout <<"Sophomore";
            break;
            case 3: cout <<"Junior";
            break;
            case 4: cout <<"Senior";
            break;
            
     }
     
     switch (cc)
     {
     
            case 'a': ttf = units * 225.40;
                         bal = ttf - dp;
                         cout <<"Your balance is " << bal;
                         cout <<"YOur ttf is " << ttf;
                         break;
                         
            case 'b': ttf = units * 325.40;
                         bal = ttf - dp;
                         cout <<"Your balance is " << bal;
                         cout <<"YOur ttf is " << ttf;
                         break;
                         
     }
     system ("PAUSE");
     return 0;
}

But it's kinda messed up.
The thing that confuses me is that you need to have two switch. One for the year level, and one for the course.
Help?

[helios]

Looks fine to me, although I would place the freshman etc. strings in an array and use yc to index it.

[Thumper]

There's nothing wrong with having two switch statements.

[Mazd]

Just we call nested switch :)

[kielmaru]

Theres nothing wrong with my code? Then why is that when I enter a number, it show's all the cout i made and it wont proceed to compute the ttf?

Also, can I have two variables in the switch (x,x)?

[LB]

Then how do you want the case statements to look?

If you really want to make one for each combination, you can do this:

struct Two
{
	int A, B;

	Two(const int& a, const int& b)
	{
		A = a;
		B = b;
	}
}

const Two PossibilityA (0,0);
const Two PossibilityB (1,0);
const Two PossibilityC (0,1);
//etc 

Two Input;
cin >> Input.A;
cin >> Input.B;

switch(Input)
{

case PossibilityA:
	//do stuff
case PossibilityB:
	//do more stuff
case PossibilityC:
	//do even more stuff, etc etc 

But as you can clearly see, it's a lot more work.

[Mazd]

Also, can I have two variables in the switch (x,x)?

i think no, for what logic?

Theres nothing wrong with my code?

here is
You have declared cc as interger int units, yc, cc;but...

  
     switch (cc)
     {
     
            case 'a': ttf = units * 225.40;//you have use it as char
                         bal = ttf - dp;
                         cout <<"Your balance is " << bal;
                         cout <<"YOur ttf is " << ttf;
                         break;
                         
            case 'b': ttf = units * 325.40;
                         bal = ttf - dp;
                         cout <<"Your balance is " << bal;
                         cout <<"YOur ttf is " << ttf;
                         break;
                         
     }

[Mazd]

this work for me ;)

#include <iostream>
#include <string>
using namespace std;
int main ()

{
     int units, yc;
     char cc;
     double dp, ttf, bal;
     
     cout <<"Enter no. of units:";
     cin >> units;
     
     cout <<"Enter your downpayment:";
     cin >> dp;
     
     cout <<"Enter your year level:";
     cin >> yc;
     
     cout <<"Enter your course:";
     cin >> cc;
     
     switch (yc)
     {
            case 1: cout <<"Freshman";
            break;
            case 2: cout <<"Sophomore";
            break;
            case 3: cout <<"Junior";
            break;
            case 4: cout <<"Senior";
            break;
            
     }
     
     switch (cc)
     {
     
            case 'a': ttf = units * 225.40;
                         bal = ttf - dp;
                         cout <<"Your balance is " << bal;
                         cout <<"YOur ttf is " << ttf;
                         break;
                         
            case 'b': ttf = units * 325.40;
                         bal = ttf - dp;
                         cout <<"Your balance is " << bal;
                         cout <<"YOur ttf is " << ttf;
                         break;
                         
     }
     system ("PAUSE");
     return 0;
}

[kielmaru]

Okay I get it now.

Can I use a switch within a switch?

[helios]

Yes, but it won't really help you, here. AFAICT, yc and cc are two completely independent variables.

[LB]

Here is an example, just for reference, of a switch inside of a switch:

switch(bleh)
{
case 1:
	//do something
case 2:
	switch(meh)
	{
	case 'a':
		//do something
	case 'b':
		//do something
	}
case 3:
	//do something
}

[Mazd]

yap! nested switch

[Mihay07]

hello..i see that you are talking about "nested switches",so y ran into a problem of my own.here is what y done so far.

int main ()
{
	char Color;
	int Fruit;
	printf("Chose what fruit you want:\n");
	printf("1-Apple\n");
	printf("2-Orange\n");
	scanf("%d",&Fruit);
	switch(Fruit){
		case 1: printf("Ok..so we have 2 types of apples:\n");
				  printf("R-Red apples\n");
				  printf("G-Green apples\n");
				  Color=getche(); //the bug is somewhere here(i think :))

				  switch(Color){
						case 'r':
						case 'R' : printf("Ty for buying red apples.10 $ please %c\n",1);
							break;
                                                case 'v' :
						case 'V' : printf("Ty for buying green apples.12$ please %c\n",1);
							break;
						default : printf("Wrong option..u blind or what?\n");
				  }
			break;
		case 2: printf("Damn..where out of oranges\n");
				  printf("1-Report the problem\n");
				  printf("2-Then get out of my shop\n");
				  //and maybe another switch/case
			break;
		default : printf("Wrong option..u blind or what?\n");
	}
	printf("\nPress Enter to continue");
	getchar();
	return 0;
}

sry for the bad formatting,just pasted it from vs and it is a bit displaced..don't now why.
So my problem is not the menu itself,y got the idea and it works fine but,the problem is when i thy to read the options from the keyboard.if y had int values,there would be no problem,but y need some char to..and my getchar() skips the second switch..i tried to use getche(),witch does not wait for you to press enter(no ecko )..and y am starting to thing that the enter thing may be the problem..tried printf("%c"&Color); but skips also..so how can y read the char options so that is going trough all switches.TY