c++ program

[mhadel]

Any year is input through the keyboard, write a program to determine whether its leap year or not.

[Bazzy]

2005
Nope, it isn't
2012
Yeah!

[cnoeval]

I wrote it on a cocktail napkin but when I tried to compile it the stupid thing jammed in my DVD drive.

Thanks a lot! :-(

mhadel: You have to try writing it yourself. We'll help you but we won't do your homework.

[Mihay07]

well,like the previous comment,you need to try to write something you're self..it is not that hard,first try to find out what exactly is a leap year,and then you can start putting theory into practice and write you're program...here is a link to wikipedia..the answer is right there between the rows.

http://en.wikipedia.org/wiki/Leap_year

[Thumper]

Homework questions always make me lol. Especially the ones that don't ask us to write one, rather command us. How about, at the very least,

Write a program to determine whether it's leap year or not please.

I'd try to make a brainfuck like hamsterman (I'm very envious of his coding) if i had the time.

[Mazd]

Any year is input through the keyboard, write a program to determine whether its leap year or not.

What is that? :0
--Homework for us?
--Command line?....yap..oh--srry

[abdallahijazi]

# include <iostream>

using namespace std;

int main ()
{
int year;

cout << "input year: ";
cin >> year;
if ( year % 4 == 0 )
cout << "\nYeah!" << endl;
else
cout << "\nNope, it isnt"<< endl;
return 0;
}

is that what you are looking for?

[cnoeval]

Sorry. Fails at year 100. But you're close.

FYI, the idea is NOT to do someones homework but rather to help them do it.

[jLNv0pDG]

Years that are evenly divisible by 100 are not leap years, unless they are also evenly divisible by 400, in which case they are leap years.

[filipe]

The wikipedia link posted by Mihay07 even has pseudo code for that. Just translate it to C++.

[helios]

Here:
(define (f n) (or (= (remainder n 400) 0) (and (= (remainder n 4) 0) (not (= (remainder n 100) 0)))))