programming exercises

[Mike200]

hello, does any one know where i can find some good c++ programming exercises. I'm looking for some fairly difficult exercises (but not impossibly difficult?). Or perhaps there is a book which is known for it's exercises?.

[Bazzy]

Try these: http://www.cplusplus.com/forum/articles/12974/
They are quite easy but they are sorted by difficulty level so you can try the last few

[chrisname]

Here you go: http://cplusplus.com/forum/articles/12974/
These range from very easy to moderately difficult. Once you've done those, you can do them again but in a more complex way. As an example, you could make a better TUI with ncurses, then make that into a GUI with Qt, make a client-server architecture (client takes input from user, server processes it and sends the results to the client to be output) or find some other way to complicate it.

You can also do these mathematical exercises: http://projecteuler.net/

Edit:
@Bazzy
FFFFFFFFFFFFFFFFFFFFFFUUUUUUUUUUUUUUUUUUUUUUU

[EverBeginner]

(but not impossibly difficult?)

Take a calculator for the computing the following:

y=(a+b)/(a-b);

Give it a name in english if you like.
Record each step giving a name.
The rest is what you are looking for.

[chrisname]

We'll call it Chrisname's Sequence.

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15

def f(a, b): return (a + b) / (a - b) for a in range(0, 4): for b in range(5, 9): a = float(a) b = float(b) print("y = f(%d, %d) = %f" % (a, b, f(a, b)))

y = f(0, 6) = -1.000000 y = f(0, 7) = -1.000000 y = f(0, 8) = -1.000000 y = f(1, 5) = -1.500000 y = f(1, 6) = -1.400000 y = f(1, 7) = -1.333333 y = f(1, 8) = -1.285714 y = f(2, 5) = -2.333333 y = f(2, 6) = -2.000000 y = f(2, 7) = -1.800000 y = f(2, 8) = -1.666667 y = f(3, 5) = -4.000000 y = f(3, 6) = -3.000000 y = f(3, 7) = -2.500000 y = f(3, 8) = -2.200000

It's not a very interesting sequence really.

[Bazzy]

Look at this:

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#include <iostream> int main() { std::cout << "y " << char ( ('a' + 'b') / ('a' - 'b') ) << " ( a + b ) / ( a - b )\n"; }

y = ( a + b ) / ( a - b )