how to give numbers to the lines

[chutzpah]

i want to give numbers to the lines of the end result but it only prints out 1 to every line. kindly help .

#include <iostream>
using namespace std;

int main () {
double f;
	double m;
	int i ;
	
	cout <<"input the value of f ";
	cin >> f ;
	
	for(f = 1;f <= 100; f++){
		m = f * 3.28;
	for (i = 1; i <=100;i++)
	
	break;
		cout<< i << " "<<  "feet conerted in to meter "<< m <<" \n"  ; 
		}
						

	 return 0;
}

[Galik]

What is the break; at line 16 supposed to do?

[Disch]

You have some questionable things here:

-) you get 'f' from the user on line 10
-) but then on line 12 you use 'f' again as a loop counter, which overwrites whatever value the user input.
-) you then have another loop on line 14 that has no body -- except for a break command, so the loop will just exit immediatley
-) then on line 17 you print 'i' as the feet entered (when really, 'f' was the feet entered, not i). Note that 'i' will always be 1 because you set it to 1 on line 14:

for( i = 1 ...

The questions you need to ask yourself are:
* Why do you have these loops?
* What purpose does 'i' serve?

[chutzpah]

Thanks, it was redundant to ask for the user input when i am specifying the f . i get it.
i tried to use 'i' so that it will give number to each line as there will 100 lines
now i took out the break it stops loop there
but then it becomes the infinite loop. so i put break here:

for(f = 1;f <= 100; f++){
		m = f * 3.28;
	for (i = 1; i <=100;i++)
	
	
		cout<< i << " "<<  "feet converted in to meter "<< m <<" \n"  ; 
                 break; // if i put break here then the first for loop gives only one value which is 3.28. it doesnt   get cumulative as it is supposed to be.
		}
				

[chutzpah]

finally i got it solved

int main() {
	double m;
double f;
int i;
i = 1 ;


	for(f = 1.00;f <= 100.00; f++){
		m = f * 3.28;

if(i<=100){
	

		cout<< i <<" "<< "  feet conerted in to meter "<< m <<" \n"  ; 
	i++;	}
						
	}
	 return 0;
}