Making a bank account display certain amounts

[BigTim]

This is my first year taking coding so I'm a bit confused cause I'm currently trying to work on this homework assignment that's a little late lol. I can make my code look and do this for my balance and counters, but I can't figure out how to for the accumulators if that makes sense? I would appreciate any help!

Balance $ 105.00
Number of checks 2
Number of deposits 2
Number of charges 2
Total checks $ 100.00
Total deposits $ 150.00
Total charges $ 45.00

#include <iomanip>      // For sring output
#include <iostream>

using namespace std;
int main()
{
	cout << fixed << setprecision(2);

	//Declarations 
	int menuOptions = 0;
	double balanceAmount = 0.0;
	double check = 0.0;
	double charge = 0.0;
	double deposit = 0.0;
	double total = 0.0;
	double totalCheck = 0;
	double totalCharge = 0.0;
	double totalDeposit = 0.0;
        int numberOfChecks = 0;
	int numberOfCharges = 0;
	int numberOfDeposits = 0;
	//Inputs
	cout << "What Is Your Balance? $" << endl;
	cin >> balanceAmount;

	do{
		//To Clear Screen
	system("cls");

	//For Switch 
	cout << "Enter Menu Options (1 For Check) (2 For Deposit) (3 For Charge) (4 To Exit) : " << endl;
	cin >> menuOptions;

	//Switch Statments/ If's
	switch (menuOptions)
	{
	case 1:
		cout << "How Much Is The Check? $" << endl;
		cin >> check;
		if (check <= balanceAmount)
		{
			balanceAmount = balanceAmount - check;
			numberOfChecks = numberOfChecks + 1;
			check = check - balanceAmount;
		}
		else 
		{
			cout << "Non Sufficent Funds, You Will Recieve a $35 NSF Fee" << endl;
			balanceAmount = balanceAmount - 35;
			numberOfCharges = numberOfCharges + 1;
			charge = (charge + 35) - balanceAmount;
			cout << "$" << total;
			cout << endl;
		}
		break;
	case 2:
		cout << "Enter The Deposit Amount: $" << endl;
		cin >> deposit;
		balanceAmount = balanceAmount + deposit;
		numberOfDeposits = numberOfDeposits + 1;
		deposit += deposit + balanceAmount;
		cout << "Your Balance After The Deposit Is" << endl;
		cout << "$" << total;
		cout << endl;
		break;
	case 3:
		cout << "What Is The Charge? $" << endl;
		cin >> charge;
		if (charge <= balanceAmount)
		{
			cout << "Your Total Will Now Be" << endl;
			balanceAmount = balanceAmount - charge;
			numberOfCharges = numberOfCharges + 1;
			charge = charge + 35;
			cout << "$" << total;
			cout << endl;
		}
		else
		{
			cout << "Your Card Has Been Declined" << endl;
		}
		break;
	case 4:
	system("cls");		//CLEAR SCREEN
			cout << " Thanks For Stoping By! " << endl;			//IN MIDDLE OF WHILE LOOPS SO TOTAL GOES FIRST
			cout << fixed << setprecision(2);
			total = balanceAmount;
			cout << " Total Amount           $" << setw(8) << total << endl;
			cout << " Number Of Checks" << setw(16) << numberOfChecks << endl;
			cout << " Number Of Deposits" << setw(14) << numberOfDeposits << endl;
			cout << " Number Of Charges" << setw(15) << numberOfCharges << endl;
			cout << " Total Check Amount     $" << setw(8) << check << endl;
			cout << " Total Deposit Amount   $" << setw(8) << deposit << endl;
			cout << " Total Charge Amount    $" << setw(8) << charge << endl;
		 while (menuOptions != 4);
		break;
	default:
		cout << "Invalid Option, Please Try Again" << endl;
	}

	}while (menuOptions != 4);
	return 0;
}

[jonnin]

sorry, what do you want it to do? Explain exactly what you want ... there are several things you can call an accumulator...

line 95 does nothing. case 4 says its 4, so you don't loop. if you did manage to loop, it would be infinite.

unimportant here but consider
x = x+3
is the same as
x+=3 ... same for all the arithmetic operators, -= *= etc exist.

also unimportant, but using int types for pennies is cleaner than doubles, which will have roundoff at some point.