Equals Operator Question

[erickulcyk]

Whats the best way to say if (a==b==c==d==e==f==8){} ?

Thanks,

Eric

[jsmith]

a == b && b == c && ... && f == 8

[Computergeek01]

if (a+b+c+d+e+f == 48){ ... }? :p

[Kyon]

Computergeek, that would not work, the following could be legit, too:
a = 16
b = 0
c = 8
d = 24
e = -8
f = 8

[Computergeek01]

But that would fall out of bounds for his origional question which was what is the best way to test if all of the integers are equal. jsmith answered it I was entering a joke, hence the emoticon. Take another look I don't even test if any of the integers are the same in my line, so it doesn't even address the same question.

[Kyon]

I know, I just wanted to point out to the OP that it doesn't work. We have no proof of any degree of skill from his side (no offense intended, erickulcyk). I just don't want people to use wrong code. If I offended you in any way, I'm sorry, I was just doing this for clarity's sake.

[hamsterman]

Abuse parentheses!
if( ( (a==b) == (c==d) ) == ( (e==f) == (f==8) ) ){ ... }
Yeah. I joking too..

[Kyon]

Sure, you're joking, only thing that needs pointing out is that you're comparing integers in the most inner ones, and then keep comparing bools. If all are equal, except for e and f, and f not being 8, it would return true.

[Disch]

int ar[6] = {a,b,c,d,e,f};
bool equal = true;
for(int i = 0; i < 6; ++i)
{
  if(ar[i] != 8)
  {
    equal = false;
    break;
  }
}

if(equal)
{
  // they all == 8
}

Note that I only mention this route as it's very likely a,b,c,d,e,f all should be an array if they're not already.

[hamsterman]

@Kyon
Oh. you're right. And that's not the only problem. It would return true for a=0 b=0, c=5, d=5, e=f=8. I guess you really can't do this without repeating every variable twice..

[Disch]

if((a&b&c&d&e&f&8) == (a|b|c|d|e|f|8))
{
  //...
}

[hamsterman]

Another one:

struct INT{
    int i;
    bool ok;

    INT(){}
    INT(int I) : i(I), ok(true){}
};

INT operator == (INT a, INT b){
    INT r;
    r.ok = a.i == b.i && a.ok;
    r.i = a.i;
    return r;
}

INT a, b, c, d, e, f;
if( (a == b == c == d == e == f == 8).ok ){ ... }

If only C++0x was here, I would have made an explicit conversion to bool..

[Athar]

While we're at C++0x:

#include <initializer_list>
template <class T> bool all_equal(std::initializer_list<T> list)
{
  for (auto it=list.begin()+1;it!=list.end();++it)if (*(it-1)!=*it)return false;
  return true;
}
[...]
if (all_equal({a,b,c,d,e,f}))...

[sequba]

i would do it this way:

if(a==b)&&(a==c)&&(a==d)&&(a==e)&&(a==f)&&(a==8))
{

}

[LB]

That's a syntax error, right there. You need another ( after the if