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Bjarne wrote: |
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What does the test do? It looks to see if the previous word we printed is different from the one we are about to print (words[i–1]!=words[i]) and if so, we print that word; otherwise, we do not. Obviously, we can’t talk about a previous word when we are about to print the first word (i==0), so we first test for that and combine those two tests using the || (or) operator: |
if (i==0 || words[i–1]!=words[i]) // is this a new word?
I want to understand how is it comparing the current string to the whole vector. |
Line number 17 is doing the actual work. But I don't understand how is it doing it. |
i==0
is true the second expression words[i–1]!=words[i]
is not evaluated.i != 0
the expression words[i–1]!=words[i]
is evaluated.i==0
i–1
would be invalid.