Avarage calculator

[walkeraki]

Hey!
I was doing some stuff and i made this

#include<iostream>
using namespace std;
int main() {
	int a,b,c;

		cout<<"Write two numbers that you want to get avarage"<<endl;
	cin>>a;
	cin>>b;
	

	c=a + b/2;

		cout<<"Your number is: "<<c<<endl;

	char z;
	cin>> z;

	return 0;
}

I get random number... i think c=a + b/2; doesn't work good.


Ty for help!

[Bazzy]

search about operator precedence and integer division

[walkeraki]

what what what? i am new to whole c++ thing ^^

[Bazzy]

Those are about mathematics

[kaduuk]

Or just add brackets around a+b... Mathematics rules state that you divide before adding.. Brackets however are to be solved before going on with the rest..

In other words, by adding brackets around the a+b, it'll first add those, and then divide it by 2 :)

[kerr021]

kaduuk right u need to add an Brackets at a+b. because in the MDAS rule. . .

[walkeraki]

ty guys