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file i/o loop

lelouch420 (2)
Hi! We're pretty far in this class now and we just did functions. For this assignment, we had to convert all of our last assignments into functions... yada yada yada. Basically, i've got my program logic complete to the point where it takes the input file, adds the data to variables for day, month, year, does calculations, and prints them to an output file. So basically everything works. Thing is, I need to have it repeat 20 times with different dates. I have absolutely no clue how to do this with the scheme i've used.

This is what a sample input file would look like for the date 5/5/1998
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5
5
1998

This is a sample output file.
 
 
Tuesday 5/5/1998 Has a day value of 35919


Basically, I can't figure out how to take an input like this:
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5
5
1998
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1999

and get an output like this:
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Tuesday 5/5/1998 Has a day value of 35919
Monday 6/3/1999 Has a day value of 35439



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#include<iostream>
#include <fstream>
#include <string>

using namespace std;

bool isLeap(int year)
{
    if (year % 400 == 0)
        return true;
    if (year % 100 == 0)
        return false;
    if (year % 4 == 0)
        return true;
    return false;
}

int days_in_month(int month, int year)

{
    if (month == 2)
    {
        if (isLeap(year))
        {
            return 29;
        }
        else
        {
            return 28;
        }
    }
    else
    {
        switch (month)
        {
        case 1:
        case 3:
        case 5:
        case 7:
        case 8:
        case 10:
        case 12:
            return 31;
            break;
        case 4:
        case 6:
        case 9:
        case 11:
            return 30;
            break;
        }
    }
    return 0;
}

int days_in_year(int day, int month, int year)
{
    int days = 0;
        for (int i = 1; i < month; i++)
        {
            days += days_in_month(i, year);
        }
    days += day;
    return days;
}

string day_of_week(int year, int day, int month)
{
    int leapAmount = (int)year / 4;
    //Calculating no of days between years
    long dayVal = (year - leapAmount) * 365 + leapAmount * 366;
    //Adding the no of days in the remaining months of given year
    for (int i = 1; i < month; i++)
    {
        dayVal += days_in_month(i, year);
    }
    //Adding the no of days entered
    dayVal += day - 2;
    int day_of_week = (int)dayVal % 7;
    switch (day_of_week) {
    case 2:
        return "Monday";
    case 3:
        return "Tuesday";
    case 4:
        return "Wednesday";
    case 5:
        return "Thursday";
    case 6:
        return "Friday";
    case 0:
        return "Saturday";
    case 1:
        return "Sunday";
    default:
        break;
    }
    return "";
}

int day_value(int day, int month, int year){
    int day_value = 0;
    for (int i = 1900; i < year; i++)
    {
        if (isLeap(i) == true)
        {
            day_value += 366;
        }
        else
        {
            day_value += 365;
        }
    }
    day_value += days_in_year(day, month, year);
    return day_value;
    }


int main()
{
    int day=0, month=0, year=0;
     
   
    ifstream input;
    input.open("input.txt");
    if (input.is_open())
    {
        input >> day >> month >> year;
        input.close();
    }

    ofstream output("output.txt");
    if (output.is_open())
    {
       output << day_of_week(day, month, year) << " " << day << "/" << month << "/" << year << " Has a day value of " << day_value(day, month, year) << "\n";
       output.close();
    }
    
 }
lastchance (6980)
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int main()
{
    int day=0, month=0, year=0;
    ifstream input( "input.txt" );
    ofstream output( "output.txt" );
    while( input >> day >> month >> year ) output << day_of_week(day, month, year) << " " << day << "/" << month << "/" << year << " Has a day value of " << day_value(day, month, year) << "\n";
}
lelouch420 (2)
Thank you. My brain is not working right now lol! so simple!
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