preventing 0 when dividing by large numbers

[yotama9]

Hi guys.

The following line:

cout << 1/1000000000;

gives 0. I thought that this is a question of representing small numbers but this line gives 0 as well:

cout << (1/1000000000) * 1000000000;

This line however is OK:

cout << 1e-9;

Why is that so?

Thanks.

[hamsterman]

1/2 will give 0 too. That is because this is integer division. Divide doubles (or floats).
either double(1)/2 or 1.0/2

[yotama9]

Got it,

thanks.