convert to an array of symbols

[laura fidarova]

Hi, i remember that someone helped me with this code here, thanks a lot for that. How can i write it as a charr array?
Q: "in a given string change all the entries of '$' to '*' until the first entry of '?' and delete all the '@' after '?' "
so it's like "$$?@@**$@" => "**?**$"

do i need to use <string.h>?

  #include <string>
#include <iostream>
#include <algorithm>
using namespace std;

int main()
{
	//string test {"$@$?@$@"};
	string test{ "$$?$@@" };

	const auto at { find (test.begin(), test.end(), '?') };

	if (at != test.end()) 
	{
		replace_if ( test.begin(), at, [](char ch) {return ch == '$'; }, '*');

		test.erase ( remove_if(at, test.end(), [](char ch) {return ch == '@'; }), test.end());
	}

	cout << test << '\n';
}

[seeplus]

You can basically keep the same code with just a couple of small changes as C++17:

#include <iostream>
#include <algorithm>
using namespace std;

int main()
{
	char test[] {"$$?@@**$@"};

	if (const auto at {find(begin(test), end(test), '?')}; at != end(test)) {
		replace_if(begin(test), at, [](char ch) {return ch == '$'; }, '*');
		test[remove_if(at, end(test), [](char ch) {return ch == '@'; }) - test] = 0;
	}

	cout << test << '\n';
}

**?**$

[lastchance]

#include <iostream>
int main()
{
   char test[] = "$$?@@**$@";
   int j = 0;
   bool first = true;
   for ( int i = 0; test[i]; i++, j++ )
   {
      if ( first )
      {
         if      ( test[i] == '$' ) test[i] = '*';
         else if ( test[i] == '?' ) first = false;
      }
      else
      {
         if ( test[i] == '@' ) j--;
         else                  test[j] = test[i];
      }
   }
   test[j] = '\0';
   std::cout << test << '\n';
}

or with pointers:

#include <iostream>
int main()
{
   char test[] = "$$?@@**$@";
   char *q = test;
   bool first = true;
   for ( char *p = q; *p; p++, q++ )
   {
      char c = *p;
      if ( first )
      {
         if      ( c == '$' ) *p = '*';
         else if ( c == '?' ) first = false;
      }
      else
      {
         if ( c == '@' ) q--;
         else            *q = c;
      }
   }
   *q = '\0';
   std::cout << test << '\n';
}