logical calculator

[John3682]

hey yall , so i have to make a logical calculator with :

(& and , | or , ~ not ,> if)

i made this with (+,-,*,/) for logical calculator (with parenthesis)it takes a INFIX turns it to POSTFIX then takes the values and calculates the final answer :

#include<iostream> 
#include<stack>
using namespace std;

int prec(char c)
{
	if (c == '^')
		return 3;
	else if (c == '*' || c == '/')
		return 2;
	else if (c == '+' || c == '-')
		return 1;
	else
		return -1;
}
string infixToPostfix(string s)
{
	std::stack<char> st;
	st.push('N');
	int l = s.length();
	string ns;
	for (int i = 0; i < l; i++)
	{
		if ((s[i] >= 'a' && s[i] <= 'z') ||
			(s[i] >= 'A' && s[i] <= 'Z'))
			ns += s[i];
		else if (s[i] == '(')

			st.push('(');
		else if (s[i] == ')')
		{
			while (st.top() != 'N' && st.top() != '(')
			{
				char c = st.top();
				st.pop();
				ns += c;
			}
			if (st.top() == '(')
			{
				char c = st.top();
				st.pop();
			}
		}
		else {
			while (st.top() != 'N' && prec(s[i]) <=
				prec(st.top()))
			{
				char c = st.top();
				st.pop();
				ns += c;
			}
			st.push(s[i]);
		}
	}
	while (st.top() != 'N')
	{
		char c = st.top();
		st.pop();
		ns += c;
	}

	return ns;

}
int E(int x, int y, char z)
{
	switch (z)
	{
	case '+':
		return x + y;
	case '-':
		return x - y;
	case '/':
		return x / y;
	case '*':
		return x * y;
	case '^':
		return pow(x,y);
	default:
		break;
	}
}
int main()
{
	string exp; cin >> exp;
	int TV, X, Y, Z;
	string S1 = infixToPostfix(exp);
	stack<int> STACK1;
	int LS1 = S1.length();
	for (int i = 0; i < LS1; i++)
	{
		if (isalpha(S1[i]))
		{
			cout << "Enter the value of ( " << S1[i] << " ) : ";
			cin >> TV;
			STACK1.push(TV);
		}
		else
		{
			X = STACK1.top(); STACK1.pop();
			Y = STACK1.top(); STACK1.pop();
			Z = E(Y, X, S1[i]);
			STACK1.push(Z);
		}
	}
	cout << "\n" << "Ur answer is : ( " << STACK1.top() << " ) \n"; 	STACK1.pop();
	
	return 0;
}

can someone please turn this code into (& and , | or , ~ not ,> if),(the values for input variables needs to be 1 or 0) ?

example of input :

~p & q <== example 1

p > q (p if q) <== example 2

(p & q) & r <== example 3


lets say p = 1 and q = 0 : p&q = 0 , p|q =1 p>q = 1 <== example

THANK YOU IN ADVANCE

[jonnin]

it works exactly the same way.
case '+':
return x + y;

becomes
case '&':
return (unsigned int)x & (unsigned int)y; //some compilers insist on unsigned for logical operations. Some do not care. The back casting to signed is up to you on the result.

boolean works too. you can return x==y (it will be 0 or 1 as an integer, 0 being false).

[John3682]

hey jonnin thank you for ur response

when i try to replace + with | or * with & the parenthesis keep printing along side with everything else , also i dont know how to show ~ (not) when theres a equation like this :

~p & q or like this ~(p|q)&r

[jonnin]

Every time I run it I get a big fat nothing. It just asks what the value of x is, or whatever, but no answer printed or anything.

what input are you feeding it before you changed it?

isnt it just computing a result, so would it not just print the value of ~(p|q)&r .. its just an integer...

if you don't see it give us the new code and the input that does not work exactly as you typed it and the expected output.

[John3682]

the code above takes an infix converts it to postfix and then calculates the answer like this :

INPUT = (a+b*c/d) turns it to postfix : abc*d/+ then asks for the value of variables like :

a=2 b=3 c=4 d=4

then the final answer: 5



i want the code to be like this :

takes something like p&q

after converting it to postfix,

ask for the values like : p=1 q=0

then the answer : p&q = 0 or false

[jonnin]

Nothing I have tried so far prints the final answer or the RP operations.

~p & q or like this ~(p|q)&r

This would do it on my calculator, but not sure its officially postfix. Maybe it helps?

p~q&

pq|~r&

[John3682]

hey guys ,i would really appreciate any help

thank you in advance

[jonnin]

post your current code. I can't make sense of the above vs what you have now and need.

[maximus854]

delete the classes bring the infix part in main function also u dont need the e class
and swap the +/-* with whatever u want