defining a class from a template class inside another class

[mmarengoni]

I have a situation similar to the one described below: there is a template class B that is inheriting from a template class A. I want to create a class type_B which is a B<int> and create an instance of this object inside a class C. I found no way to do this so far. Any hint? I am using Dev C++ in Windows 10, but I don't think this is a problem...

 template <class T> class A{

	protected:
		T *item;
		int t;
	
	public:
		A(int s){
			item = new T[s];
			t=s;
		}
		
		void in(const T& elem, int p){
			item[p]=elem;
		}
		
		print(){
			for(int i =0; i< t; i++){
				cout<<item[i]<<" ";
			}
			cout<<endl;
		}
};

template <class Z> class B:public A<Z>{
	private:
		int position=0;
	public:
		B(int s):A<Z>(s){
		}
		
		void in(const Z& elem){
			A<Z>::in(elem, position);
			position++;
		}
};


class C{
	protected:
		typedef B<int> B_type;
		B_type element(5);
	
	public:
		C(){
			
		}
		
	
};

[closed account oivD8vqX]

#include<iostream>
template <class T> class A{

	protected:
		T *item;
		int t;
	
	public:
		A(int s){
			item = new T[s];
			t=s;
		}
		
		void in(const T& elem, int p){
			item[p]=elem;
		}
		
		void print(){
			for(int i =0; i< t; i++){
				std::cout<<item[i]<<" ";
			}
			std::cout<<std::endl;
		}
};

template <class Z> class B:public A<Z>{
	private:
		int position=0;
	public:
		B(int s):A<Z>(s){
		}
		
		void in(const Z& elem){
			A<Z>::in(elem, position);
			position++;
		}
};


class c{
	protected:
		typedef B<int> b_type;
        b_type element{5};
	
	public:
		c(){ }
	
};

int main() {
    c c;
}

I'm pretty sure I don't understand what your problem is, but this does compile.

[coder777]

Line 17: The return type is missing. Probably void.

Line 42: The round brackets are wrong for initializing. Use curly brackets instead.