Way to prevent calling default constructor of Base class?

[x loto]

Hi!

I have a Base class with a default constructor (parameterized with default value) and a Derived class with the same. I'm wondering if there's a way to call the Derived constructor and explicitly avoid calling the one for the Base first. Here's an example of the situation, with its output:

#include <iostream>
#include <fstream>

using namespace std;

class Base
{
   public:
   Base(ifstream* FILE = NULL)
   {
      cout << "Base constructor!" << endl;
   }
};

class Derived: public Base
{
   public:
   Derived(ifstream* FILE = NULL)
   {
      cout << "Derived constructor!" << endl;
   }
};

int main()
{
   Derived X;
   return 0;
}

Base constructor!
Derived constructor!

So, is there a way to prevent the Base ctor from being called first? Thanks in advance!

[m4ster r0shi]

Sure! Make a dummy constructor and call that instead:

#include <iostream>
#include <fstream>

using namespace std;

class Base
{
   public:
   Base(ifstream* FILE = NULL)
   {
      cout << "Base constructor!" << endl;
   }

   Base(int,int){}
};

class Derived: public Base
{
   public:
   Derived(ifstream* FILE = NULL):Base(0,0)
   {
      cout << "Derived constructor!" << endl;
   }
};

int main()
{
   Derived X;
   return 0;
}

[x loto]

Oh! I had completely forgotten the ctor syntax with the colon--I knew there had to be a way! Thank you!

This is what I get for not doing any coding at all for almost seven years and then trying to take on a large project....grumble grumble.... ;-)