Need a hint

[aniemira]

I have been working on the following problem the entire weekend:

Write a program that repeatedly asks for positive integers (values greater than or equal to 1). The user
may type 0 to quit the program. The user will enter at least one value before typing 0 to quit. After the
user types 0 to quit, your program should report how often the largest number was entered.

My teacher said that he wrote this program using only a while loop and two if statements, I understand how to use the while loop. However I am not sure how to display the largest value of all the numbers or print how often that number was entered. I also understand that all the numbers entered must be stored in order to compare them. I would greatly appreciate help or some hints on this.

Thank you

[Bazzy]

Create two variables, one to store the current max value and one to store the number of times it's entered ( initialize both to 0 )
When a number is entered use those variables to keep track of the max value

[aniemira]

I made two variables, however I am having trouble making an if statement that will use a variable to keep track of the max value.

[binarybob350]

pseudo code:

int maxValue = 0;

while( user does not enter 0 )
{
  if value user just entered is greater than maxValue 
    then set maxValue to that value
}

print out maxValue

[aniemira]

I have everything right except that I cannot seem to write an if statement to act as a counter for the number of times that the largest value occurs

[AdventWolf]

int MaxValue = 0
int MaxCount = 0


while(etc..)
{
    if...etc
   
    if( number == maxValue)
        MaxCount++
}

Is that what you need?

[aniemira]

I tried that, it did not work for all cases of numbers I was testing

[aniemira]

int main()
{
    int maxValue=0;
    int r=0;
    int n;
    cout<<"Enter a positive integer (0 to quit) :";
    cin>>n;
    while(n !=0)
    {    
        if(n>maxValue)
        {
            maxValue=n;
        }
         cout<<"Enter a positive integer (0 to quit) :";
        cin>>n;
        cout<<"Got it."<<endl;
        
        if(n == maxValue)
        {
           r++;
        }
       
    }
    cout<<"Done."<<endl;
    cout<<"Largest input:"<<maxValue<<"."<<endl;
    cout<<"Number of "<<maxValue<<"'s:"<<r<<endl;

This is what I have

[Disch]

The logic here has 2 steps:

1) If the user inputs a number equal to the maximum, then you count it

2) If the user inputs a number higher than the maximum, that number is your new maximum, and you start the count over.

[AdventWolf]

What Disch said, you've got to reset the value of r to 0 when n>maxValue.