Beginner : Read n, sum even numbers until exceeds n

[kid]

Hello.I am trying to make this program work. Because I am learning by myself c++ my only option to ask question witch I don't know the answer is on the internet.The exercise sounds like this:Reads an integer n with at most four digits. Display all the natural numbers in ascending order as long as their sum exceeds n.And if you are trying to type a character , you type again.
This is my code so far.Can someone point me to the right direction? I don't want code, I want to figure this by myself. I don't know where is the mistake.

#include <iostream>
#include <conio.h>
using namespace std;


int main(){
	int number;
	int sum = 0;
	cout << "Reads an integer n with at most four digits. Display all the natural numbers" << "\n"
		 << " in ascending order as long as their sum exceeds n." << endl;
	while ( (number != 0) & (number < 0) & (number > 9999) )
		{
			cout << "Write a pozitive number and smaller than 9999 \n"; 
			cin >> number;
			while (!(cin >> number))
			{
				cin.clear();
				cout << '\a';
				while (cin.get() != '\a')
				continue;
				cout << "Write a pozitive number and smaller than 9999 \n";
				for ( int i = 0; i < number; i++ )
					if ( (i%2 == 0) & (sum < number) )
						{
						sum = sum + i; // sum += i;
						cout << sum << " " << endl;
						}
			}
		}  //(number < 0) || (number > 9999)
	_getch();
	return 0;
}

Thank you. Excuse my poor English.

[binarybob350]

At first glance I see alot of problems.

3 problems with outer while loop
while ( (number != 0) & (number < 0) & (number > 9999) )
Using number before you read it in.
You are using & which is bitwise and, you want && which is logical and.
Also how can number be less than 0 and greater than 9999 at the same time, loop will never execute

your reading in number twice.

cin >> number;
while (!(cin >> number))
{

No idea what you are doing here

cin.clear();
cout << '\a';
while (cin.get() != '\a')
  continue;

[kid]

Now the program looks like this. But I can't figure how to make it work.I forgot to mention above : Display all the natural even number in ascending order as long as their sum exceeds n.

do {
   cout << "Write a pozitive number and smaller than 9999, 0 to exit.";
   cin >> number;
   cout << endl;
      if ((number > 1) && (number < 9999)){
           for ( int i = 0; i < number; i++ )
                if ( (i%2 == 0) && (sum < number) ){
                sum = sum + i;
               cout << sum << " ";
           }
      cout << endl;
      }
} while (number != 0);

Thank you for the reply. I really appreciate it.
Here

cin.clear();
cout << '\a';
while (cin.get() != '\a')
  continue;

i was trying to make something like this : if you type a character instead of a number it makes a sound and you type again

[kid]

#include <iostream>
#include <conio.h>
using namespace std;


int main(){
    int number, sum = 0, even = 0;
    cout << "Enter a number: " << endl;
    cin >> number;
    while  (sum < number) 
    {
          cout << even << " ";
          even = even + 2; // even += 2
          sum = sum + even; // sum += even
       }
    _getch();
    return 0;
}
Thank you.