using a function of a class which I'm in.

[yotama9]

Hi guys.

I don't know if I framed the question correctly. I'll try to explain it by code. Let's say I have two classes a and b in the following way:

class a{
   int rr;
  public:
   a();
   ~a();
}

class b{
   a aa;
  public:
   b();
   ~b();
   void doDomthing();
}

Is there a way to run the "doSomthing()" function of b from a function within aa?

I hope I'm clear.

Yotam

[Bazzy]

I'm not sure I understand, do you mean something like this?

class a{
   int rr;
  public:
   a();
   ~a();
   void foo();
};

class b{
   a aa;
  public:
   b();
   ~b();
   void doSomething();
};

void A::foo ()
{
   b bb;
   bb.doSomething();
}

[yotama9]

yes.

The idea is that I'll have a class box, and another class, lipid. each box contains lipid and the lipids might change their location from box to box.

[Galik]

You need to have access to an object of type class B in order to call one of B's member functions on it. So as long as the functions in class A have access to a B object you can do it. This might be member variables of class A like this:

class A
{
    B b; // member of type class B
public:
    void func()
    {
        b.doSomething(); // run the function on b
    }
};

[yotama9]

Is there a way to pass a specific member in a class to a subclass? That is, I want a to use a function of b (and not B).