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what is the function of cin.ignore and cin.get at the same time?

unknown1412 (3)
what is the function of cin.ignore and cin.get at this program?
location : 57-58

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#include <iostream>
#include <stdlib.h>
using namespace std;

char square[10] = {'o','1','2','3','4','5','6','7','8','9'};

int checkwin();
void board();

int main()
{
int player = 1,i,choice;

char mark;
do
{
board();
player=(player%2)?1:2;

cout << "Player " << player << ", enter a number: ";
cin >> choice;

mark=(player == 1) ? 'X' : 'O';

if (choice == 1 && square[1] == '1')

square[1] = mark;
else if (choice == 2 && square[2] == '2')

square[2] = mark;
else if (choice == 3 && square[3] == '3')

square[3] = mark;
else if (choice == 4 && square[4] == '4')

square[4] = mark;
else if (choice == 5 && square[5] == '5')

square[5] = mark;
else if (choice == 6 && square[6] == '6')

square[6] = mark;
else if (choice == 7 && square[7] == '7')

square[7] = mark;
else if (choice == 8 && square[8] == '8')

square[8] = mark;
else if (choice == 9 && square[9] == '9')

square[9] = mark;
else
{
cout<<"Invalid move ";

player--;
cin.ignore();
cin.get();
}
i=checkwin();

player++;
}while(i==-1);
board();
if(i==1)

cout<<"==>\aPlayer "<<--player<<" win ";
else
cout<<"==>\aGame draw";

cin.ignore();
cin.get();
return 0;
}

/*********************************************
FUNCTION TO RETURN GAME STATUS
1 FOR GAME IS OVER WITH RESULT
-1 FOR GAME IS IN PROGRESS
O GAME IS OVER AND NO RESULT
**********************************************/

int checkwin()
{
if (square[1] == square[2] && square[2] == square[3])

return 1;
else if (square[4] == square[5] && square[5] == square[6])

return 1;
else if (square[7] == square[8] && square[8] == square[9])

return 1;
else if (square[1] == square[4] && square[4] == square[7])

return 1;
else if (square[2] == square[5] && square[5] == square[8])

return 1;
else if (square[3] == square[6] && square[6] == square[9])

return 1;
else if (square[1] == square[5] && square[5] == square[9])

return 1;
else if (square[3] == square[5] && square[5] == square[7])

return 1;
else if (square[1] != '1' && square[2] != '2' && square[3] != '3'
&& square[4] != '4' && square[5] != '5' && square[6] != '6'
&& square[7] != '7' && square[8] != '8' && square[9] != '9')

return 0;
else
return -1;
}


/*******************************************************************
FUNCTION TO DRAW BOARD OF TIC TAC TOE WITH PLAYERS MARK
********************************************************************/


void board()
{
system("cls");
cout << "\n\n\tTic Tac Toe\n\n";

cout << "Player 1 (X) - Player 2 (O)" << endl << endl;
cout << endl;

cout << " | | " << endl;
cout << " " << square[1] << " | " << square[2] << " | " << square[3] << endl;

cout << "_____|_____|_____" << endl;
cout << " | | " << endl;

cout << " " << square[4] << " | " << square[5] << " | " << square[6] << endl;

cout << "_____|_____|_____" << endl;
cout << " | | " << endl;

cout << " " << square[7] << " | " << square[8] << " | " << square[9] << endl;

cout << " | | " << endl << endl;
}

/*******************************************************************
END OF PROJECT
********************************************************************/
Last edited on
dutch (2548)
Edit your post and put code tags around your code like this:
[code]
your code here
[/code]

Do you know what cin.get() does? Have you read the manual page?
Do you know what cin.ignore() does? Have you read the manual page?
Last edited on
unknown1412 (3)
yes i already read some information about what cin.get and cin.ignore do, but still cant figure it out about the conection in this program
coder777 (8444)
The operator>> leaves a newline in the stream. So if you call get() without ignore() the get() function would return immediately. It shouldn't hence the ignore() which removes the newline.
dutch (2548)
As coder777 said, except that proper structure would dictate putting the cin.ignore() after the cin >> choice, since that statement should clean up after itself. Then it's not needed (and in fact an error) in the other places.

This code is very badly written. Not good code to study.
Last edited on
unknown1412 (3)
oh ok guys thx, i understand a litle bit
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