operator overloading
Hi All,
I had a very stupid doubt but I couldn't seem to understand this thing.
When I am overloading ++ operator , I need to provide int in the parameter and i can't use void. But essentially I am not using that variable as I am increasing the value of whatever is there only by a constt 1.
Why is it then, that i still need to provide and int parameter and void doesn't work ?
Sincerely,
Neeraj
I had a very stupid doubt but I couldn't seem to understand this thing.
When I am overloading ++ operator , I need to provide int in the parameter and i can't use void. But essentially I am not using that variable as I am increasing the value of whatever is there only by a constt 1.
Why is it then, that i still need to provide and int parameter and void doesn't work ?
Sincerely,
Neeraj
The reason is that the compiler needs to differentiate between two operators with an identical symbol ++.
There is pre-increment ++i; and there is post-increment i++;
So to distinguish between the two the function signature needs to be different. So the int parameter is a bit of a hack to solve the ambiguity.
There is pre-increment ++i; and there is post-increment i++;
So to distinguish between the two the function signature needs to be different. So the int parameter is a bit of a hack to solve the ambiguity.
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