some simple questions

[Zhuge]

Just repeatedly ask for the amount he sold for until they input "0", at which case the program should assume that is the end of sales.

[empror9]

welcome Zhuge (726)

yes but i don't understand the steps

could you please tell me the steps then i can write algorathim

1- what should i do

2- ..... etc

[empror9]

please see this code

#include <iostream> 
using namespace std; 
int main() 
{ 
int sum; 
int num1,num2; 
sum = 0; 
cout << "Enter two numbers: "; 
cin >> num1 >> num2; 
while(num2 >= num1){ 
cout << num1 << " "; 
sum = num1 + num1; 
num1++; 
} 
cout<<"Sum = " << sum; 
        return 0; 
}

i;m trying to output the numbers between the two input numbers and then find their sum

this is an example

num1 = 2
num2 = 6

output = 2 3 4 5 6, sum = 120

my code is working but i cant find the correct sum

please help

waiting for you

[filipe]

Firstly, 2 + 3 + 4 + 5 + 6 == 20!

Secondly, you're resetting the value of sum on every loop iteration. You should do this instead:

sum += num1;

[empror9]

thanks it's working now

so can you help me witgh Q1??

[empror9]

thanks it's working now

can you help me with Q1? could write to me the code buecause i dont know how to write for it

[empror9]

where are you guys

[m4ster r0shi]

Did you ask your teacher what does "solve this formula" mean? What did he tell you?

[empror9]

welcome

he didn't reply :(

[empror9]

hello again

please see this code

#include<iostream> 
using namespace std; 
int main() 
{ 
float s=0,p; 
int i,j,x; 
 
cout<<"x="; 
cin>>x; 
x++; 
 
for(j=1;j<=6;j++) 
{ 
p=1; 
for(i=1;i<=j;i++) 
p*=x; 
 
if(j%2==0) 
s+=(-p/j); 
else 
s+=(p/j); 
} 
cout<<"ln("<<x<<")="<<s<<endl; 
system("pause"); 
return 0; 
}

and this is the equation http://img571.imageshack.us/img571/3935/70196195.jpg

so is this the correct code for the euation??

i want just to make sure

[helios]

No.

[empror9]

so how :(

[m4ster r0shi]

Remove this -> x++;

Also turn this -> cout<<"ln("<<x<<")="<<s<<endl; into -> cout<<"ln("<<x+1<<")="<<s<<endl;

Oh, and x should be a float.

[empror9]

hello m4ster

this is the code

#include<iostream> 
using namespace std; 
int main() 
{ 
float s=0,p; 
int i,j;
float x; 
cout<<"x="; 
cin>>x; 
for(j=1;j<=6;j++) 
{ 
p=1; 
for(i=1;i<=j;i++) 
p*=x; 
 
if(j%2==0) 
s+=(-p/j); 
else 
s+=(p/j); 
} 
cout<<"ln("<<x+1<<")="<<s<<endl; 
system("pause"); 
return 0; 
}

so this one is correct now, am i right?

you know my problem is in math, i'm really poor in math :(

[empror9]

and i want to edit this code to accept one number and then show the numbaer whether is a prime or not

this is the code and i try to edit but i couldn't

int num,isprime;
cout <<"Please enter a number: ";
cin >> num;
for(int i=2; i<=num;i++)
{
isprime = 1;
for(int j=2; j<=i ; j++)
{
if( i == j)
continue;
else if( i % j == 0){
isprime = 0;
}
}
if(isprime == i){
cout<<i<<"is a prime number ";
}else{
cout<<i<<"is not a prime number ";
}
}

[empror9]

please help me!

[Galik]

Regarding this: http://img571.imageshack.us/img571/3935/70196195.jpg

Why don't you write a function to evaluate one of the terms of the series?

double calc_term(double x, int n)
{
    // calculate xn/n here
}

Then call that function in a loop, alternatively adding or subtracting each term from n = 1 to n = 6?