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// See the Cormen book for details of the following algorithm
#include<stdio.h>
#include<limits.h>
// Matrix Ai has dimension p[i-1] x p[i] for i = 1..n
int MatrixChainOrder(int p[], int n)
{
/* For simplicity of the program, one extra row and one
extra column are allocated in m[][]. 0th row and 0th
column of m[][] are not used */
int m[n][n];
int i, j, k, L, q;
/* m[i,j] = Minimum number of scalar multiplications needed
to compute the matrix A[i]A[i+1]...A[j] = A[i..j] where
dimension of A[i] is p[i-1] x p[i] */
// cost is zero when multiplying one matrix.
for (i=1; i<n; i++)
m[i][i] = 0;
// L is chain length.
for (L=2; L<n; L++)
{
for (i=1; i<n-L+1; i++)
{
j = i+L-1;
m[i][j] = INT_MAX;
for (k=i; k<=j-1; k++)
{
// q = cost/scalar multiplications
q = m[i][k] + m[k+1][j] + p[i-1]*p[k]*p[j];
if (q < m[i][j])
m[i][j] = q;
}
}
}
return m[1][n-1];
}
int main()
{
int arr[] = {1, 2, 3, 4};
int size = sizeof(arr)/sizeof(arr[0]);
printf("Minimum number of multiplications is %d ",
MatrixChainOrder(arr, size));
getchar();
return 0;
}
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im trying to learning matrix chain multiplication using dp, but i find it hard to code it by myself,
especially i dont quite understand the role of i,j,k,L here
even to understand this code i need quite long time like a day ...
and i realize that i cant code it if i dont understand the role of each variable
i know L is for the partition of chain matrix, it can be 2,3,4
but what is role of i,j,k?
and how can i know the loop for i is until n-L+1
and what is role of k?
i know its like filling table but after i made table and trace , i still dont understand
for this part, q = m[i][k] + m[k+1][j] + p[i-1]*p[k]*p[j];
its hard to come up with this equation p[i-1]*p[k]*p[j];
can someone explain, how to code this problem, and also some problem that require understanding of 3 variable like i ,j ,k in loop,
do you trace and make strategy first?