Day, Month Date Calculation.

[anasnanjo]

This code works.

  #include <iostream>
#include <string>
using namespace std;



class DayOfYear
{
private:

public:
	 int MonthDays[13] = {0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334, 365 };
	 string MonthName[13] = {"", "January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December" };
	 void print(int);
};



void DayOfYear::print(int day)
{
	int month = 0;

	while (DayOfYear::MonthDays[month] < day)
		month = (month + 1) % 12;

	
	cout << DayOfYear::MonthName[month] << " " << day - DayOfYear::MonthDays[month - 1];
};


int main()
{
	DayOfYear dYear;

	

	int day;
	//Ask user the total day number
	cout << "\nEnter a number you would like to convert into a month and day "<<endl;
	cin >> day;

	//Error check for negative numbers and numbers higher than one year
	if (day <= 0 || day > 365)
	{
		cout << "You must enter a valid number (1 thru 365)" << endl;
	}

	
	dYear.print(day);
	
	cout << endl;
	system("pause");
	return 0;
}

[anup30]

leap year?

[Duthomhas]

It doesn’t work for leap years.

[dutch]

It still tries to print the day even if the input is bad.

[Duthomhas]

It is a very good effort though.

Add code to compute whether or not you are in a leap year, and get the correct year (either from the user or the current year). Then you can adjust depending on the number of days in February.