end program from function

[arg57]

I decided just to end the game, If they get it correct, they can move on to the next turn. If they do not get it correct after the second attempt, the game is over. I'm not sure how to do that from a function

int obs3()  //function obstruction 3
{
	int choice, tries{ 1 };
	cout << " What object do you use to read \n"
		<< " data typed at the keyboard ?\n"
		<< " 1. ( cin )\n"
		<< " 2. ( print )\n"
		<< " 3. ( cout )\n"
		<< " 4. ( enter )\n"
		<< " Enter 1, 2, 3 or 4 \n";
	cin >> choice;

	while (choice != 1)
	{
		cout << " Try again\n";
		cin >> choice; 
		if (tries = 3)
			cout << " Sorry; you failed to overcome the obstacle\n";
		return 0;
		tries++;
		
		return 0;
		}
    cout << " Thats correct\n";
	return 0;
}
  

[dhayden]

You could put that code in a function that's called from main(). The function might return true/false depending on whether the user wants to play again or not.

[Grand Master stickshift]

does this work in a way that you wanted

#include "pch.h"
#include <iostream>
using namespace std;
int obs3()  //function obsruction 3
{
	int choice, tries = 0;
	cout << " What object do you use to read \n"
		<< " data typed at the keyboard ?\n"
		<< " 1. ( cin )\n"
		<< " 2. ( print )\n"
		<< " 3. ( cout )\n"
		<< " 4. ( enter )\n"
		<< " Enter 1, 2, 3 or 4 \n";
	cin >> choice;

	int Choice = 0;
	bool BOOL;

	while (BOOL = true)
	{
		
		std::cout << "try again(1)Yes-(2)No\n ";
		std::cin >> Choice;
		if (Choice == 1)
		{
			BOOL = true;
			++tries;
		}
		else if (Choice == 2)
		{
			break;
		}
		
		if (tries == 3)
		{
			cout << " Sorry; you failed to overcome the obstacle\n";
			break;
		}
	}
}

[arg57]

thanks but that does pretty much what I have. I decided just to end the game, If they get it correct, they can move on to the next turn. If they do not get it correct after the second attempt, the game is over. Thanks again

[arg57]

I did it used;

system("pause");
exit (0);