Looping issue

[Rubes]

I can't figure out this formatting loop. The program finds out if a number is divisible by a certain number and if it is then it outputs the numbers it is divisible by in a row. My issue is that the rows can only be 8 numbers long with spaces and then it needs to start a new row with the rest of the numbers. And after that I need to reverse the output so small numbers-->bug and vise versa. The way I have it now does not stop at 8 and only goes from big to small and I can't figure it out.

#include<iostream>
#include<iomanip>
using namespace std;
int num1,n=2,total;
int main()
{
cout<<"Enter a number: ";
cin>>num1;
cout<<num1<<" is divisible by: ";
while(n<num1)
{
    total=num1/n;

    if (num1%n==0)
    {
        cout<<total<<" ";
    }

    n++;
    total=0;
}

return 0;
}

output:

Enter a number: 360
360 is divisible by: 180 120 90 72 60 45 40 36 30 24 20 18 15 12 10 9 8 6 5 4 3 2


//needs to show as--- 360 is divisible by:
180 120 90 72 60 45 40 36
30 24 20 18 15 12 10 9
8 6 5 4 3 2

360 is divisible by:
2 3 4 5 6 8 9 10
12 15 18 20 24 30 36 40
45 60 72 90 120 180

[dutch]

Your spec is unclear. Show a couple example input/outputs.

[Rubes]

alright I updated it to show what it is outputting and how the output is supposed to look

[E0p9LyTq]

Quick and dirty:

#include<iostream>

int main()
{
   const int row_count = 8;

   std::cout << "Enter a number: ";
   int num1;
   std::cin >> num1;
   std::cout << '\n';

   std::cout << num1 << " is divisible by:\n";

   int n     = 2;
   int count = 0;

   while (n < (num1 / 2 + 1))
   {
      if (num1 % n == 0)
      {
         int total = num1 / n;

         std::cout << total << '\t';

         count++;

         if (count % row_count == 0)
         {
            std::cout << '\n';
         }
      }

      n++;
   }
   std::cout << '\n';

   std::cout << "\nReversed, " << num1 << " is divisble by:\n";

   n     = num1 / 2 + 1;
   count = 0;

   while (n > 1)
   {
      if (num1 % n == 0)
      {
         int total = num1 / n;

         std::cout << total << '\t';

         count++;

         if (count % row_count == 0)
         {
            std::cout << '\n';
         }
      }

      n--;
   }
   std::cout << '\n';
}

Enter a number: 360

360 is divisible by:
180     120     90      72      60      45      40      36
30      24      20      18      15      12      10      9
8       6       5       4       3       2

Reversed, 360 is divisble by:
2       3       4       5       6       8       9       10
12      15      18      20      24      30      36      40
45      60      72      90      120     180