How to check in character?

[Mehmood Umer]

Hi...
This program check numbers that is palindrome or not in reverse order i want to make this program for characters checks palindrome or not like(MOM,MADAM)...

 #include<iostream>
using namespace std;
main()
{
	long int n, num, digit, rev=0;
	cout<<" Enter  a  positive  number:";
	cin>>num;
	n=num;
	do
	{
		digit=num%10;
		rev=(rev*10)+digit;
		num=num/10;
	}
	while(num!=0);
	cout<<" The  reverse  of  the  number  is : "<<rev<<endl;
	if(n==rev)
	cout<<" The  number  is  palindrome";
	else
	cout<<" The  number  is  not  palindrome";
}

[dutch]

What's stopping you?

[Mehmood Umer]

how to make??

[blackmamba]

just start checking from front and behind till the middle. if any char mismatches then not palindrome. if u reach middle with all char matching then its a palindrome.

[Mehmood Umer]

how??

[Grime]

Do it like you did it with numbers.

First, take a string.
Iterate from its last index to its first index and for every character, append to a new string (just like how you appended to rev using maths but here you do it directly).

Compare both strings. And voila you're done.

Quick mentions:
1) Strings have an operator for +, so you can use += to append to a string.
2) You can use .length() or .size() on a string to get its size.
3) You have to iterate from last index to first index, keep in mind (or you could reserve memory on the second string and use indexes).
4) If you were to use cstrings then do the same but with strlen() instead and you can use strcmp() for comparing (for strings you can just use == operator).

[honeybuzz]

Well @Grime's approach would work but if you want to save the extra space, then you could do:-

s = "MADAM"
l = 0
r = len(s) - 1
while(l < r){
 if(s[i] != s[r]){
   print("Not a palindrome");
   break;
}
l++;
r--;
}
if(l >= r)
   print("Palindrome")

[Mehmood Umer]

Thanks Grime and honeybuzz