Trouble with array

belsimo (2)
Hello!

I have filled an array with 100 random numbers beetven 1 and 6. Now i want to count how many of each i have and print the result such as:

You have 23 of the number 1.
You have 12 of the number 2.

and so on.
But i can't get it to work.

Does anyone have an idea?

//ingemar
closed account (z05DSL3A)
Post your code so people can see what you have done, then they can make suggestions as where to go from there.
belsimo (2)
hello!

The problem are that i haven't got any idea how to solve this part. I have search the internet and in books after a way to count through an array after specifik values but i can't find anything.

this is how i fill the array:

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#include "stdafx.h"
#include "yatizw.cpp"
#include "Die.h"



int _tmain(int argc, _TCHAR* argv[])
{
    
    int result;
    int diceNr[100];
    int insert;
    



for(int count = 0; count <=99; count++)
       {
   Die mydie1;
   mydie1.rollDie();
   result = mydie1.getDieValue(); 
   diceNr[count] = result;
   
}
Zaita (2770)
Your best approach would be to use a map to achieve this.

e.g.
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map<int, int> mCombinations;

for (int i = 0; i < 100; ++i) {
 map[diceNr[i]]++;
}

map<int, int>::iterator mPtr = mCombinations.begin();
while (mPtr != mCombinations.end()) {
 cout << "You have " << (*mPtr).second << " of the number " << (*mPtr).first << endl;
 mPtr++;
}


That should be roughly in the playing field of what you require.
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