Still battling with doublyLinkedLists

I have written another program.
It runs but then it bombs out after listing all the elements in the list.

Here is what I get:
Enter integers ending with -999
67 54 23 6 -999

List 1: 6, 23, 54, 67
Process returned 255 (0xFF) execution time : 22.674 s
Press any key to continue.


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 #include <iostream>
using namespace std;

template <typename T>
class list {

// ostream & operator<<(ostream & out, const list<T> &);

//ostream & operator<<( const list<T>& list)
//{
//node *p;
//int num;

//for(p = list.first; p != 0; p = p -> next)
    //std::cout << p -> num;
    //return p;
//}
friend std::ostream& operator << (std::ostream& out , list<T>& obj)
{
     std::string separator = "";
    for (node* n = obj.first; n != NULL; n = n->next)
    {
        out << separator;
        separator = ", ";
        out << n->value;
    }

    //return out << "]";
}
 public:

    list();                                   // constructor
    list(const list &l);                      // copy constructor
    list &operator=(const list &l);           // assignment operator
    ~list();                                  // destructor

    // Returns number of elements in the list
    unsigned size();

    // Returns true if the list is empty, false otherwise.
    bool isEmpty() const;

    // Inserts element to front of list
    void insertFront(const T &val);

    // Inserts element to the end of list
    void insertBack(const T &val);

    // Returns the values of the front element in the list
    T front();

    // Returns the value of the back element of the list.
    T back();

    // Deletes the front element of the list and returns its value
    void removeFront();

    // Deletes the back element of the list and returns its value
    void removeBack();

    // Prints each element of the list in order
    void printForward();

    // Prints each element of the list in reverse order
    void printReverse();

 private:
    struct node {
      node   *next;
      node   *prev;
      T      value;
    };

    node   *first; // The pointer to the first node
    node   *last;  // The pointer to the last node
    unsigned length; // holds number of elements in the list

    // Initializes empty list
    void createEmpty();

    // Removes all of the elements in the list
    void removeAll();

    // Makes copy of all of the elements in the list
    void copyAll(const list &l);

};

template <typename T>
void list<T>::createEmpty() {
  first = NULL;
  last = NULL;
  length = 0;
}

template <typename T>
void  list<T>::removeAll() {
  while (!isEmpty()) {
    removeFront();
  }
}

template <typename T>
void list<T>::copyAll(const list &l) {
  node *iterator = l.first;
  while (iterator) {
    T obj = iterator->value;
    insertBack(obj);
    iterator = iterator->next;
  }
}

template <typename T>
unsigned list<T>::size() {
  return length;
}

template <typename T>
bool list<T>::isEmpty() const{
  return (first == NULL && last == NULL);
}

template <typename T>
void list<T>::insertFront(const T &val) {
  length++;
  node *newNode = new node;
  new (&(newNode->value)) T(val);
  newNode->next = first;
  newNode->prev = NULL;
  if (isEmpty()) first = last = newNode;
  else {
    first->prev = newNode;
    first = newNode;
  }
}

template <typename T>
void list<T>::insertBack(const T &val) {
  length++;
  node *newNode = new node;
  new (&(newNode->value)) T(val);
  newNode->next = NULL;
  newNode->prev = last;
  if (isEmpty()) first = last = newNode;
  else {
    last->next = newNode;
    last = newNode;
  }
}

template <typename T>
T list<T>::front() {
  return first->value;
}

template <typename T>
T list<T>::back() {
  return last->value;
}

template <typename T>
void list<T>::removeFront() {
  if (isEmpty()) return;
  length--;
  node *removedNode = first;
  first = first->next;
  if (first) first->prev = NULL;
  else first = last = NULL;
  delete removedNode;
  return;
}

template <typename T>
void list<T>::removeBack() {
  if (isEmpty()) return;
  length--;
  node *removedNode = last;
  last = last->prev;
  if (last) last->next = NULL;
  else first = last = NULL;
  delete removedNode;
  return;
}

template <typename T>
list<T>::list() {
  createEmpty();
}

template <typename T>
list<T>::list(const list &l) {
  createEmpty();
  copyAll(l);
  return;
}

template <typename T>
list<T>& list<T>::operator= (const list &l)
{
    if (this != &l) {
        removeAll();
        copyAll(l);
    }
    return *this;
}

template <typename T>
list<T>::~list() {
  removeAll();
}

template <typename T>
void list<T>::printForward() {
  if (isEmpty()) {
    std::cout << "List is empty\n";
    return;
  }
  node *head = first;
  while (head) {
    std::cout << head->value << " ";
    head = head->next;
  }
  std::cout << "\n";
}

template <typename T>
void list<T>::printReverse() {
  if (isEmpty()) {
    std::cout << "List is empty\n";
    return;
  }
  node *tail = last;
  while (tail) {
    std::cout << tail->value << " ";
    tail = tail->prev;
  }
  std::cout << "\n";
}
#include <iostream>

using namespace std;

int main()
{
    list<int> list1, list2;
	int num;

   std::cout<<"Enter integers ending with -999"<<endl;

	cin>> num;

	while(num != -999)
	{
		list1.insertFront(num);
		cin >> num;
	}
	std::cout<<endl;

	std::cout<<"List 1: " <<list1 << endl;

	list2 = list1;     //test the assignment operator;

	std::cout <<"List 2: " << list2 <<endl;

	std::cout<<"Enter the number to be deleted: ";

	cin>> num;
	std::cout<< endl;

	list2.removeFront();

	std::cout<<"After deleting the node, ";
	   std::cout<<"List 2: "<<endl <<list2;
	    std::cout<<endl;
 return 0;

}

It bombs out before I can copy the list and test the delete operation
I believe you just have to return out; on line 28.

Compiler warnings often find errors like this for you. GCC with -Wall tells me that the function has no return value when it is supposed to.

In C++ we use nullptr, not NULL, for dealing with pointers that point to nothing. I'm not the right person to explain the details of why, but perhaps this will help explain:

https://stackoverflow.com/questions/20509734/null-vs-nullptr-why-was-it-replaced
Last edited on
This is not the way to do it:
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    node *newNode = new node;
    new (&(newNode->value)) T(val);  // gratuitous use of placement-new
    newNode->next = first;
    newNode->prev = NULL;

Instead, make a constructor for node and use it:
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    struct Node {
        Node* next;
        Node* prev;
        T     value;
        Node(T value, Node* next, Node* prev)
            : next(next), prev(prev), value(value) {}
    };

// Use it like this instead of those other 4 lines:

    node *newNode = new node(val, first, nullptr);

Replace the other use of placement-new, too.
Last edited on
Shouldn't operator << just call printForward()?

Adding Browni3141's suggestion, the program works for me.
I fixed my copy constructor and got it to work!!!! FINE

Thank you all
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