int * numchar() can not return an int

[johnnylo]

write the function numchr(). the function has two parameters: a const char * s pointing to the first character in a C-style string, and a char c. return the number of times that c appears inside s

HI, my problem is i keep getting the memory location of char * s, how to i fix it so that i will return an int??

int * numchr(const char * s, char c)
{
    
 int  * count = 0;

  while(*s)
  {
     if (*s == c) *count++;   
      
      s++;
  }
    
}

[Denis]

Do insist that function should return int*? Maybe better to return just int?

if it should be int*, than

int * numchr(const char * s, char c)
{
    int  * count(new int(0));

  while(*s)
  {
     if (*s == c) *count++;   
      
      s++;
  }
   return count;
    
}

But don't forget to free memory by delete when pointer will be unneeded

[johnnylo]

i don't know what int* is but the function has to to return an int value such as 3..

after i fixed it with your code i still keep getting this "0x370f2c" from my instructor's Junit test.

[Denis]

As I think you don't understand difference between pointers and variables.
this should be help

int numchr(const char * s, char c)
{
    int  count(0);

  while(*s)
  {
     if (*s == c)count++;   
      
      s++;
  }
   return count;
    
}