Drawing a Diagonal

[CosmicInferno]

I'm new to this. I want this to result in a diagonal line.

#include <iostream>

using std::cout; using std::endl; using std::cin;

int main() 
{
	cout << "Input size: ";
	int size;
	cin >> size;
	for (int i = 0; i < size; i++)
	{
		for (int j = 0; j == i; j++)
		{
			cout << "+";
		}
		cout << endl;
	}
	cout << endl;
}

The results are just:
Input size: 4
+

What I want:
Input size: 4
+
*+
**+
***+

Note: Pretend * are empty spaces

[CosmicInferno]

#include <iostream>

using std::cout; using std::endl; using std::cin;

int main() 
{
	cout << "Input size: ";
	int size;
	cin >> size;
	for (int i = 0; i < size; i++)
	{
		for (int j = 0; j < size; j++)
		{
			if (j != i)
				cout << " ";
			else
			cout << "+";
		}
		cout << endl;
	}

NVM I think I solved it.

Edit: Actually is there a way to do it with out the if else. By that I mean by having it output + and not have to use
" ".

[mbozzi]

Actually is there a way to do it with out the if-else

for (int i = 0; i < size; i++)
{
    // print i spaces
    for (int j = 0; j < i; ++j) 
        std::cout << ' ';
    // then print a + followed by a new-line:
    std::cout << "+\n";
}

You can't eliminate printing the spaces entirely, unless you choose to treat standard output like a terminal rather than an output stream and control it specifically. This can't be done in a standard way, and not at all if standard output was going to a file instead.

[Jaybob66]

or

for (int i = 0; i < size; i++)
    std::cout << std::string(i,' ') << "+" << std::endl;

[Manga]

At cosmicInferno,

You had a correct solution except line12.

for (int j = 0; j == i; j++)

Like this...

#include <iostream>

using std::cout; using std::endl; using std::cin;

int main() 
{
	cout << "Input size: ";
	int size;
	cin >> size;
	for (int i = 0; i < size; i++)
	{
		for (int j = 0; j < i; j++)
		{
			cout << " ";
		}
		cout << "+" << endl;
	}
	cout << endl;
}