for loop help

i'm trying to make a loop that repeats steps 2-6 of my algorithm until user chooses to close the window. could anyone give me an example of what that would look like. I've checked other forums and can't seem to find one that i can apply to mine. thanks in advance.
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/*
Program prompts user to enter two points in the form (x1, y1) and (x2, y2) and finds the distance between the two points using a function.
Algorithm steps:
	1. Define a function called findDistance (...) that takes four parameters x1, y1 and x2, y2 as two points.
		a. finds the distance between them using the equation: sqrt//FIX ME sqrt symbol ((x2-x1)^2 + (y2-y1)^2)
		b. returns the calculated distance value
	2. Prompt user to enter four numbers
	3. Convert the values into float and store them into variables
	4. Call function getDistance by passing 4 entered numbers as arguments
	5. Display results with proper description.  Format output numbers to 2 decimal points.
	6. Test and validate that program output is correct for a given set of input points.
	
*/


#include <iostream>
#include <cstdio>
#include <cassert>
#include <cmath>
using namespace std;





const double epsilon = 1e-6; // 0.000001 accuracy upto 6 decimal points


// function prototypes
// function that calculates the distance between two points
// x1, y1 and x2, y2 and returns the calculated value double findDistance (int, int, int, int);

// test function that runs automated testing void test();

double findDistance(int x1, int y1, int x2, int y2)
{
	//int x1, y1, x2, y2; // can not get rid of c4700
	//x1 = 0;
	//y1 = 0;
	//x2 = 0;
	//y2 = 0;
	//cout << sqrt((x2 - x1) ^ 2 + (y2 - y1) ^ 2) << endl;
	cout << sqrt(pow(x2 - x1, 2) + (y2 - y1, 2)) << endl;
	//FIXME - Find the distance between (x1, y1) and (x2, y2)
	// following the algorithm step 1
	// return the calculated distance
	return 0.000000;
}

void test()
{
	assert(findDistance(4, 3, 5, 1) - 2.23607 <= epsilon);
	assert(findDistance(3, 5, 7, 0) - 6.40312 <= epsilon);
	assert(findDistance(-1, 2, 4, 18) - 16.76305 < epsilon);
	// FIXME - add atleast two more test cases
	cout << "all tests passed..." << endl;
}

	int main()

{
 
	double distance; 
	int x1, y1, x2, y2; // variables to store two points (x1, y1) and (x2, y2)
	x1 = 0;
	y1 = 0;
	x2 = 0;
	y2 = 0;
	char ch;
	distance = findDistance(x1, y1, x2, y2);
	//for (int main = 1; main(findDistance) <= 10;)
	system("cls");
	cout << "Program calculates distance between 2 points on a 2d Coordinates." << endl;
	cout << "Enter a point in the form (x, y) : ";
	// parse the input stream
	cin >> ch >> x1 >> ch >> y1 >> ch; // value stored in ch is ignored
	printf(" (x1, y1) = (%d, %d)\n", x1, y1);

	cout << "Enter a second point in the form (x, y): ";
	cin >> ch >> x2 >> ch >> y2 >> ch; // value store in ch is ignored
	printf(" (x2, y2) = (%d, %d)\n", x2, y2);
	//FIXME - Read/parse the second point and store data into variables x2 and y2 //fixed
	test();
	//FIXME - Call test function // fixed
	//findDistance(x1, y1, x2, y2);
	//FIXME - call findDistance function passing proper arguments //
	printf("The distance between the 2 points =  ", distance);
	cout << findDistance(x1, y1, x2, y2) << endl;
	//FIXME - using printf function display the returned distance with proper description

	cin.ignore(1000, '\n');
	cout << "Good Bye!" << endl;
	cin.get();
	return 0;
}
I should fix line 43 first.
You could try a while loop for this sort of thing.
Why do you want to repeat those steps? And is there a specific number of times you want to go through the loop?
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