assignment problem. unsure what title to describe my problem

[clio78]

i have a piece of an unfinished program.
try to run it...
if you go straight to option 3 and input values, how do i output these values in option 4 ?
i tried outputting my declared variables
it wont work ? why is this ?
i apologize the code is so long

I hope someone can tell me how i'd go about it

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#include <iostream> //the usual headers are used including string #include <string> #include <conio.h> void WeeklySales(); //these are functions i created void yesnofunc(); main() { int number; // declare variables char answer; double sales, sales_amount, quantity, total_sales, vat, commission; sales = (sales_amount * quantity); //initialise variables total_sales = (sales + vat); do { //start of a do-while loop //output displays the menu cout << "\n\n******Sales System******"; cout << ("\n\n"); cout << "1. Display Company Logo.\n"; endl; cout << "2. Input/Validate weekly sales data.\n";endl; cout << "3. Calculate weekly sales.\n";endl; cout << "4. Display reciept.\n";endl; cout << "5. SHUT DOWN & LOG OFF.\n";endl; cout << "\nEnter a number...\n";endl; //prompts the user cin >> number; cout << ("\n\n"); switch (number) //<--the expression is a variable (number) & controls //the switch the value of (number) is tested against a list of //constants. When a match is found, the statement sequence //assosciated with that match is executed. { case 1: //<----- const = 1 //displays the company logo cout << "\n\tUU\tUU \tEEEEEEEE \tLL\t\t \SSSSSSS\n\tUU\tU"; cout << "U \tEE \t\tLL\t\tS\n\tUU\tUU \tEE \t\tLL\t\tS\n\t"; cout << "UU\tUU \tEEEEEEE \t\LL\t\t\ SSSSSS\n\tUU\tUU \tEE"; cout << " \t\tLL\t\t S\n\tUU\tUU \tEE \t \t\LL "; cout << "\t\t S \n\t UUUUUUUU *\tEEEEEEEE *\tLLLLL"; cout << "LL *\tSSSSSSS *\n\n\n\n\n"; //the break statement causes program flow to exit from the entire switch statement break; case 2: cout << ("\nWeekly sales data\n\----------------- "); break; case 3: cout << ("\nCalculate weekly sales \n\n"); cout << "\n\nWould you like to calculate the weekly sales ? \n"; cin >> answer; //a switch within a switch switch (answer) { case 'n': //<---if 'n' is entered the text is ouputted cout << "\n\n\nThank You!\n\n"; break; //<----break takes it out of the switch case 'y': //<---if 'y' then program is run below //variables declared double sales, sales_amount, quantity, total_sales, vat; total_sales = sales + vat; cout << "\n\nTOTAL SALES = sales amount * quantity\n" << endl; cout << "\nEnter the sales amount\n"; cin >> sales_amount; cout << "\nEnter the quantity\n" ; cin >> quantity ; sales = (sales_amount * quantity); cout << "\n" << sales_amount << " * " << quantity << " = " << sales << "\n"; cout << "\n" << "Sales is: \t" << sales << "\n"; vat = 0.175*sales; total_sales = (sales + vat); cout << "\nTOTAL SALES inc VAT is: \t" << total_sales << "\n"; if(total_sales<25) cout << " and No commission"; else if(total_sales<50) cout << "\n5% commission of total sales is " << 0.05 * total_sales ; else if(total_sales<75) cout << "\n10% commission of total sales is " << 0.10 * total_sales; else if(total_sales>75) cout << "\n20% commission of total sales is " << 0.20 * total_sales; } break; case 4: //how would i display total sales and sales entered above in case 3 ? cout << ("\nDisplay receipt \n\n"); cout << "\nUELS\n"; cout << "----\n\n"; cout << total_sales << "\n";

cout << sales; break; case 5: cout << ("\nGoodbye, and thank you for using U.E.L.S. \n\n");break; //default statement sequence is executed if no matches are found default: cout << ("Enter a number from 1-5 only!\n\n\n\n\n\n"); } } while (number !=5); //program will NOT stop looping till 5 is entered getch(); } void yesnofunc() { char answer; do { cout << "\nIs this correct ?\n"; cin >> answer; switch (answer) { case 'y': cout << "\nThank you!!\n"; break; } }while (answer != 'y'); }

[Albatross]

Do you want the values outputted automatically, so that regardless of whether you chose 3 or 4, and execute what is in 4?

If so, an if statement outside of the switch block might be useful.

And check your code in 3: What happens if total_sales is equal to 75?

-Albatross

[clio78]

if the total_sales is 75, wouldnt the second be executed ?
i guess i should use >= and <=

[Galik]

You may find it helpful to move the code for each case: statement into functions.

That way it is easier to see the program flow separate from the details.

A bit like this. But its entirely up to you:

void display_the_menu()
{
	cout << "\n\n******Sales System******";
	cout << ("\n\n");
	cout << "1. Display Company Logo.\n"; endl;
	cout << "2. Input/Validate weekly sales data.\n";endl;
	cout << "3. Calculate weekly sales.\n";endl;
	cout << "4. Display reciept.\n";endl;
	cout << "5. SHUT DOWN & LOG OFF.\n";endl;
	cout << "\nEnter a number...\n";endl; //prompts the user
}

int get_menu_input()
{
	int number;
	cin >> number;
	return number;
}

void display_the_company_logo()
{
	// ...
}

void display_receipt()
{
	// ..
}

void calculate_weekly_sales()
{
	// ..
}

int main()
{
	do
	{
		display_the_menu();
		number = get_menu_input();
		cout << ("\n\n");

		switch(number)
		{
			case 1: //<-----  const = 1
				display_the_company_logo();
				break;

			case 2:
				cout << ("\nWeekly sales data\n\----------------- ");
				break;

			case 3:
				cout << ("\nCalculate weekly sales \n\n");
				cout << "\n\nWould you like to calculate the weekly sales ? \n";
				cin >> answer;

				switch(answer)
				{
					case 'n':
						cout << "\n\n\nThank You!\n\n";
						break; 
					case 'y': 
						calculate_weekly_sales();
				}
				break;  // REMOVE THIS if you want case 4 to always run after case 3:

				case 4:
					display_receipt();
		}
	}
	while(1);
}

If you look at line 66 above if you remove that break statement then if the user opts for 3, number 4 will also run. The break; statement stops that happening.

[clio78]

thank you Galik.