Finding specific row or column in 2D array

[FreeSocks]

Hello guys !

So i'm working on this task, where i have to find a specific column or row given to me by the user. But it works fine till i end up trying to display the second or third row, in which case it prints out all the rows not only the one i specify.

int A[3][3];

class Matrix {
public:
	int value;
	int row;
	int col;
	string answer;
	void printArray();
	void showRow(int a);
	void showCol(int c);
};

int main()
{
Matrix m;
	

	while (true)
	{
		cout << "Would you like to see a row or a column?(r/c) : " << endl;
		cin >> m.answer;
		if (m.answer == "r") {
			cout << "Which row would you like to see ?" << endl;
			int chosenRow;
			cin >> chosenRow;
			cout << endl;
			m.showRow(chosenRow);
		}
	}
    return 0;
}

void Matrix::printArray() {
	for (int i = 0; i < 3; i++) {
		for (int y = 0; y < 3; y++) {
			cout << A[i][y] << " ";
		}
		cout << endl;
	}
}

void Matrix::showRow(int a) {
	for (int j = 0; j <= a; j++) {
		for (int b = 0; b < 3; b++)
			cout << A[j][b] << endl;
		}
}

void Matrix::showCol(int c) {
	for (int g = 0; g <= c; g++) {
		for (int h = 0; h < 3; h++) {
			cout << A[h][g] << endl;
		}
	}
}

I understand it might be a bit messy , and im kinda new to C++ and trying to figure stuff out.
I'm trying not to use pointers or adresses and keep it simple as possible. The printArray function works fine.

But as i mentioned, the showRow and the showCol, work fine if i only want to display the first column or row.. if i want to display the second or third it shows all previous rows or columns.

I also have a code where the user inputs the specific values for the row/column but i cut it out as its too long and bunch of none important code to this question. So just by default, there are some values for each position of a row or a column in the array.

[lastchance]

@freesocks,
You are trying to use nested loops because that is what you used for a whole matrix, when you were having to loop through BOTH rows and columns.

But if you want a SPECIFIC row, for example, then you DON'T want to loop over rows, you just want to keep that specific row.

Consider your code here:

void Matrix::showRow(int a) {
	for (int j = 0; j <= a; j++) {
		for (int b = 0; b < 3; b++)
			cout << A[j][b] << endl;
		}
}

Here, you are telling it to loop over rows j=0,...,a but you only need row j=a.
In fact, you don't need the variable j at all, as it is always equal to a.
So remove the outer loop:

void Matrix::showRow(int a) {
		for (int b = 0; b < 3; b++)
			cout << A[a][b] << endl;
}

See if you can do the same with a particular column.

[FreeSocks]

Oh my gawd...

I did it correct the first time, why did i choose to make it a nested loop..

Bless ya my friend :)

EDIT: An additional question i would like to ask..

Is it possible that when i display or show the Rows, i see them horizontaly like when i display the whole array ?

Because it displays it like a column 1 after another, not sideways? Just more visually representative ?

[lastchance]

void Matrix::showRow(int a)
{
   for (int b = 0; b < 3; b++) cout << A[a][b] << " ";
   cout << endl;
}

[FreeSocks]

Thanks works like a charm!

I feel so bad for not realising how to format it more properly <.<