How would you solve this problem

[thecomputernerd01]

Given an integer n (input from the user), write a C++ program that determines the equivalent of n in the roman numerals. The user will provide a value of n greater than 0 and less than 4000.

this is what i have but it doesn't go up to 4000
Would you use the switch function in order to do this?
thanks.

  #include <cstdlib>
#include <iostream>

using namespace std;

int main()
{
	int n;
	
	cout << "Enter n ";
	cin >> n;
	
	if ( n >= 10){
		cout << "X";
		n = n - 10;
	}
	if ( n >= 10){
		cout << "X";
		n = n - 10;
	}
	if ( n >= 10){
		cout << "X";
		n = n - 10;
	}
	/*
		n is a number < 10
	*/
	
	if ( n == 9 ) {
		cout << "IX";
		n = n - 9;
	}
	
	/*
		n is a number <= 8
	*/
	if ( n >= 5) {
		cout << "V";
		n = n - 5;
	}
	/*
		n is a number <= 4
	*/
	
	if (n == 4) {
		cout << "IV";
		n = n - 4;
	}
	
	/*
		n is a number 1,2,3
	*/
	
	if( n >= 1){
		cout << "I";
		n = n - 1;
	}
	if( n >= 1){
		cout << "I";
		n = n - 1;
	}
	if( n >= 1){
		cout << "I";
		n = n - 1;
	}
	//system("pause");
	return 0;
}

[icy1]

You need loops