Ending an infinite loop

[cienb]

I am new to C++ and loops give me a hard time.
There is a never ending infinite loop although break statements are include after each case.

Any help would be appreciated.

#include <iostream>
#include <iomanip>
#include <string>
#include <istream>

using namespace std;

int main()
{
int lstring;
int x;
int countWords(string str);
int countConsonant(string str, int);
int consonant;
string str, str2;

char selection;

cout << "Please enter a word, a sentence, or a string of numbers." << endl;
getline(cin, str); //user input

lstring = str.length(); //length of string
str2 = str;

bool another = true;

while (another)
{
cout << "\nUSE THIS MENU TO MANIPULATE YOUR STRING" << endl;
cout << "---------------------------------------" << endl;
cout << "1) Inverse String" << endl;
cout << "2) Reverse String" << endl;
cout << "3) To Uppercase" << endl;
cout << "4) Count Number Words" << endl;
cout << "5) Count Consonants" << endl;
cout << "6) Enter a Different String" << endl;
cout << "7) Print the string" << endl;
cout << "Q) Quit" << endl;
cin >> selection;

switch (selection)
{
case '1':
for (x = 0; x < lstring; x++)
{
if (islower(str[x]))
str[x] = toupper(str[x]);
else if (isupper(str[x]))
str[x] = tolower(str[x]);
}
break;

case '2':
for (x = 0; x < lstring; x++)
{
str[x] = str2[lstring - 1 - x];
}
break;

case '3':
{
for (x = 0; x < lstring; x++)
{
if (islower(str[x]))
str[x] = toupper(str[x]);
}
}
break;

case '4':
cout << "\nThe string \"" << str << "\" has " << countWords(str) << " word(s)" << endl;
break;

case '5':
consonant = 0;
cout << "\nThe number of consonants in the string is " << countConsonant(str, consonant) << "." << endl;
break;

case '6':
cout << "\nEnter a different string : " << endl;
cin.ignore();
getline(cin, str);
break;

case '7':
cout << "\nThe current string is: " << str << endl;
break;

case 'Q':
cout << "\nYou have chosen to quit the program. Thank you!" << endl;
break;

case '9':
cout << "\nInvalid selection. Please try again." << endl;
}
}

//system("PAUSE");
return 0;
}


int countWords(string str)
{
int length = str.length();
int words = 1;
for (int size = 1; length > size; size++)
{
if (str[size] == ' ' && str[size - 1] != ' ')
words++;
}
if (str[0] == ' ')
words--;
return words;
}

int countConsonant(string str, int consonant)
{
int length = str.length();
consonant = 0;

for (int i = 0; i < length; i++)
{
if (str[i] != 'a' && str[i] != 'e' && str[i] != 'i' &&
str[i] != 'o'&& str[i] != 'u' && str[i] != 'A' && str[i] != 'E'
&& str[i] != 'I' && str[i] != 'O' && str[i] != 'U' && str[i] != ' ')
consonant = consonant + 1;
}
return consonant;
}

[SECMoG1T]

those breaks can only get you out of the switch not the loop, the loop runs by checking the variable "another" you should include code such that when the user want's to quit "another" is set to false;

case 'Q':
cout << "\nYou have chosen to quit the program. Thank you!" << endl;
another = false;
break;