displaying time variable if time is between x time and y time

[andy371]

Hey sorry if the name is stupid, but I'm really not too sure what it is I am trying to do, I'll try make it easy to help.
I basically have something like this example:

int main ()
{
  time_t rawtime;
  tm * ptm;

  time ( &rawtime );

  ptm = gmtime ( &rawtime );

  puts ("Current time around the World:");
  printf ("GMT-11     :  %2d:%02d\n", (ptm->tm_hour+gmt011) %24, ptm->tm_min);
  printf ("GMT-10     :  %2d:%02d\n", (ptm->tm_hour+gmt010) %24, ptm->tm_min);

and what I want to do is, make the output of either of the last 2 lines into the input for a variable, so I can make all from gmt-12 through to gmt+13 a variable. Then I want to be able to output only the variable that's time is in between now and then (3 and 4 o'clock for e.g).

This is what I was trying to do, but don't think it is right at all.

    if (ptm->tm_hour %24, ptm->tm_min > '03:00')
  {
                     printf ("GMT/UTC    :  %2d:%02d\n", (ptm->tm_hour) %24, ptm->tm_min);
  }
  else
  {
      cout << "fail";
  }

I hope that makes sense, I do not wish for my puzzle to be solved for me through this, just to get taught from a person what I am doing, and the basics of going about it, as I have tried searching and that, but don't even know what to search for in the end of it =\. I am a true beginner.. Thanks in advance for any help you can provide.