enter like matrix

[1vf9z8AR]

the code works fine but i want to input the values like a matrix but instead it inputs in a weird way.

#include<iostream>
using namespace std;
int main()
{
    int r,c;
    int *value;
    cout<<"Enter number of rows";cin>>r;
    cout<<endl;
    cout<<"Enter number of columns";cin>>c;
    cout<<endl;
    value=new int[r*c];

    if(!value)
        cout<<"Out of memory"<<endl;

        cout<<"Enter 2-D array"<<endl;
    for(int i=0;i<r;i++)
    {
        for(int j=0;j<c;j++)
        {
            cin>>value[i*c+j];
                cout<<"\t";
        }
            cout<<endl;
    }

    cout<<"Displaying your 2-D array"<<endl;
    for(int i=0;i<r;i++)
    {
        for(int j=0;j<c;j++)
        {
            cout<<value[i*c+j]<<"\t";
        }
        cout<<endl;
    }
    return 0;
}

The output is perfect.

[coder777]

cin outputs all user input including the newline:

Enter number of rows2

Enter number of columns2

Enter 2-D array
1
	2
	
3
	4
	
Displaying your 2-D array
1	2	
3	4

This is also possible:

Enter number of rows2

Enter number of columns2

Enter 2-D array
1 2 3 4
		
		
Displaying your 2-D array
1	2	
3	4

Unfortunately there is nothing you can do to change this behavior of cin. If you want another input scheme you need to do this in another way like pdcurses.

[Enoizat]

#include<iostream>

int main()
{
    std::cout << "\nEnter number of rows: ";
    int r {};
    std::cin >> r;

    std::cout << "Enter number of columns: ";
    int c {};
    std::cin >> c;

    int* value = new int[r*c];

    if(!value) { 
        std::cout << "Out of memory\n";
        return 0;
    }

    std::cout << "Enter 2-D array - please press ENTER after each value:\n";
    for(int i=0; i<r; i++)
    {
        for(int j=0;j<c;j++)
        {
            std::cout << "\tPlease enter data for row " << i+1 
                      << " column " << j+1 << ": ";
            std::cin >> value[i*c+j];
        }
        std::cout << '\n';
    }

    std::cout << "Displaying your 2-D array:\n";
    for(int i=0; i<r; i++)
    {
        for(int j=0; j<c; j++)
        {
            std::cout << value[i*c+j]<<"\t";
        }
        std::cout << '\n';
    }
    return 0;
}

Please have a look at the warnings about your indentation: there's a subtle error in your code logic.