not sure why the cout returns 65.

[ahswong]

Can someone please explain to me why cout << someChar << " "
<< someInt << endl; returns A 65? I understand why it returns A but not sure why 65 as shown on my terminal. Thanks!

#include <iostream>
#include <cmath>
#include <iomanip>
using namespace std;

int main() {
  int someInt,
       w = 5, x = 9, y = 2, z = 7;
   char someChar = 'A';
       cout << "tryIt3A output \n";
    z += 3;
    cout << z << "  " << z % w << endl;
   z *= w + y;
    cout << z << endl;
    z -= 60.1;
    cout << z << endl;
    cout << (x-1) / (x-w) * y << endl;
    cout << (x-1) / ((x-w) * y) << endl;
    cout << static_cast<double>(x) / y << endl;
    cout << x / y << endl;
    cout << (w + x % 7 / y) << endl;
    cout << (abs(y - w) + sqrt(x)) << endl;
    someInt = someChar;
    cout << someChar << "  "
         << someInt << endl;
    return 0;
}

[Flaze07]

there's

someInt = someChar;

and because the ascii number of A is 65, someInt becomes 65

[ahswong]

got it! thanks for explanation!