Changing value in a two-dimensional Array

This is my code so far, and in seat_available(seatingArray), I am trying to get values that have already been passed through, changed to "X", and have the "X" replace the number that was there before it. So it looks like the seat was taken.
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  #include <iostream>
#include <cmath>
#include <iomanip>
#include <cstdlib>
#include <windows.h>

using namespace std;

void use_array();
void display(int seatingArray[9][8]);
void seat_available(int seatingArray[9][8]);

int main()
{
    int seatingArray[9][8] ={
 { 40, 50, 50, 50, 50, 50, 50, 40 },
 { 30, 30, 40, 50, 50, 40, 30, 30 },
 { 20, 30, 30, 40, 40, 30, 30, 20 },
 { 10, 20, 20, 20, 20, 20, 20, 10 },
 { 10, 20, 20, 20, 20, 20, 20, 10 },
 { 10, 20, 20, 20, 20, 20, 20, 10 },
 { 10, 10, 10, 10, 10, 10, 10, 10 },
 { 10, 10, 10, 10, 10, 10, 10, 10 },
 { 10, 10, 10, 10, 10, 10, 10, 10 } };


display(seatingArray);

seat_available(seatingArray);
}
void use_array()
{

}
void display(int seatingArray[9][8])
{
cout << setw(55) << "Available Theater Seating\n\n";
        for(int i=8;i > 0; i--)
        {
        cout << "\n";
        for(int q = 7; q > 0; q--)
            {
            cout << setw(8) << "$ " << seatingArray[i][q];
            }
        }
    cout << endl;
}


void seat_available(int seatingArray[9][8])
{
    int row, column;
    char X;
    for(int i = 72;i > 0; i--)
    {
    cout << "\n Please select a Theater Seat Row:" << "\n";
    cin >> row;
    cout << "Please select Theater Seat Column" << "\n";
    cin >> column;
    cout << "Thank you for choosing seat # " << row << ":" << column << "\n";
    cout << "Your ticket price is :$" << seatingArray[row][column] << "\n";
        if(seatingArray[row][column] == X)
        {
            cout << "ATTENTION: THE SEAT SELECTED, Row " << row << ", Column " << column << " DOES NOT EXIST.";
        }
    seatingArray[row][column] = X;
    Sleep(1500);
    system("CLS");
    display(seatingArray);
    }
}
Shouldn't each element of seatingArray, representing a specific seat, be unique?
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