Entering many numbers into a loop

[ENh0ko23]

For this i have to first specify how many numbers i am going to enter. Then i have to enter how many numbers i said.
For ex: i say i will enter 4 numbers then i enter 4 numbers. Now i know how to do what i mentioned. The only problem i have is making this code work with random numbers. Say next time i want to enter 10 numbers. I am confused on how i would write this code to work for every number i want to use. Or if i wanted to enter 3 numbers or 7 numbers

#include <iostream>
using namespace std;
int main()
{
	int counter = 0,
		num;

	cout << "Please enter how many numbers you are going to use." << endl;
	cin >> num;
	cout << "Please enter " << num << " integer(s) seperated" << endl;
	cin.get();



	cin.get();
	return 0;
}

[joe864864]

I'm not exactly sure what your asking, but I believe the answer to your question is that you will need to use a loop to allow the user enter a number as many times as they specified. For example, you could do something like this:

	int num, temp;
	vector<int> nums;

	cout << "Please enter how many numbers you are going to use." << endl;
	cin >> num;
	
	for (int count = 0; count < num; count++)
	{
		cout << "Please input a number for position " << count << endl;
		cin >> temp;
		nums.push_back(temp);
	}

	cout << "Nums: ";
	for (int count = 0; count < num; count++)
	{
		cout << nums.at(count);
	}
	cout << '\n';