got finite output (do... while)

[mys 97]

hello. i am trying to make a program to prove Lothar Collatz formula. the program should produce output until the num = 1, but my code seems work pretty wierd. The output are only 6 (finite). i already try to figure it out what the problem but still cannot correct it. fyi, i am a beginner.

here is my code.

#include <iostream>

using namespace std;

int main ()
{
int x;

cout << " ##### This program will prove about LOTHAR COLLATZ formulae #####" << endl;

cout << endl;

cout << " Please enter any positive integer... : ";
cin >> x;

do
{
cout << x <<" ";

if (x % 2 == 1)
{
x = (3 * x) + 1;
}
else
x = x / 1;


}while (x != 1);




return 0;
}

[lastchance]

Should be
x = x / 2;
not
x = x / 1;

If you succeed in "proving" it, please let us know.

[xxvms]

I have done this for someone else here :)

#include <iostream>
#include <cstdlib>
using namespace std;


int main()
{
	int inputNumber = 0;

	cout << "Please type number: ";
	cin >> inputNumber;
	

	for  (; inputNumber >= 2;)
	{
		if (inputNumber % 2 == 0)
		{
			inputNumber = inputNumber / 2;
			cout << inputNumber << " ";
		}
		else
		{
			inputNumber = ((inputNumber * 3) + 1);

			cout << inputNumber << " ";
		}
	}
	
	system("pause");

    return 0;
}

[lastchance]

I think this came up under another sobriquet not so long ago, too:
http://www.cplusplus.com/forum/beginner/206995/#msg977825

[mys 97]

owh... hahahah.. how can i miss look that things. its proved. thanks a lot btw