Comparing vector elements or address?

[kingkush]

I want to compare the actual object stored in the vector. I was wondering if this is comparing the address or the value of the object in the vector. The > operator has been overloaded for this object.
selectedHandB and selectedHandA are pointers

if((&selectedHandB)[0] > (&selectedHandA)[0])
    {
        std::cout << " B > A " << std::endl;
    }

[jonnin]

looks a pointer comparison to me.

(&b) address of b, which is already a pointer you say, so this is now a ** to an object. [0] thanks to () pulls it back to the original.

That is, if I am reading it right, your code is identical to

if( selectedHandB > selectedHandA) because the & and [0] cancel out.

Others can double check me. This is what happens when you write things with a convoluted style ... it is confusing to read.

[TheIdeasMan]

I don't know what your exact situation is, but:

If you are using vectors, why do you need pointers?

Prefer references over pointers, where you can.

If operator> is overloaded, why send it pointers?

You can look in the debugger to see what is happening.

[kingkush]

My apologies if adding () made it too difficult for you to read. It's easier for me to visually see it this way.

And I want to use references but I have a structure of pointers (to vectors) of objects (class) to determine who goes first and in what order. They then decide which cards they want. Line 3 was irrelevant. It was just to check to see if the address or element was being compared. It was in fact the element but i was curious why it isn't a *.

Is there a more efficient way of doing this?