error: ‘g’ does not name a type

[hatecpp]

Hello. I want to create a class and set some values. Unfortunately this code gives me error that is stated in the title.

  #include <iostream>
  int main ()
  {
  return 0;
  }
  class fall
  {
    public:
     double g, m , t, v, x, w;
     g = 9.81;
  };

[jonnin]

you can't do that here.
you have to assign the value in the constructor function.

fall::fall()
{
g = 9.81;
}

or you can make it a constant.

const double g = 9.81;

a class is a variable type. It does not execute code directly inside the definition. All code has to be in one of the member functions.

[joe864864]

jonnin is correct. This should help you in the right direction.

#include <iostream>

using namespace std;

class fall
{
public:

	fall();//defalt constructor
	fall(double, double, double, double, double);//overloaded constructor


	double get_g()//getfunction for g
	{
		return g;
	}
private:
	double m, t, v, x, w;//variables
	const double g = 9.81;
};

fall::fall()//defualt constructor
{
	m = 0;
	t = 0;
	v = 0;
	x = 0;
	w = 0;
}

fall::fall(double m, double t, double v, double x, double w)//overloaded constructor
{
	this->m = m;
	this->t = t;
	this->v = v;
	this->x = x;
	this->w = w;
}

int main()
{
	fall object1;//create object1

	cout << "G: " << object1.get_g() << endl;//just shows that it works

	return 0;
}

[hatecpp]

Thank you @jonnin and @joe864864. But it seems too confusing :/. I need to study constructors.