error in my code

[teopeishen]

i have done the code. But when running it, it cannot do more than 3 instruction. Please help. Thnx in advance.

 #include <stdio.h>

int main()

{
	int id; 
	float hour,hourrate;
	float gross,net;
	float averagepay;
	printf("Salary Calculator:\n");
	printf("\tPlease insert identification number:");
	scanf("%d",& id);
	printf("\tPlease insert your hourly wage rate:");
	scanf("%.2f",& hourrate);
	printf("\tPlease insert your number of hours worked:");
	scanf("%.2f",& hour);
	if (hour<=40)
	{
		gross=hour*hourrate;
		return 0;
	}
	else
	if(hour>40)
	{
		gross=40*hourrate+(hour-40)*hourrate*0.5;
		return 0;
	}
	net=gross-(gross*3.625/100);
	averagepay=net/7;
	printf("%d\n",id);
	printf("\toverall total net pay:%.2f\n",net);
	printf("\taverage net pay:%.2f\n",averagepay);
	getchar();
	return 0;
}

[Enoizat]

What errors did you get? I slightly modified your code just to examine it and it seems fine:

#include <cstdio>

int main()

{
    printf("Salary Calculator:\n");

    printf("\tPlease insert identification number: ");
    int id; 
    scanf("%d", &id);

    printf("\tPlease insert your hourly wage rate: ");
    float hourrate;
    scanf("%f", &hourrate);

    printf("\tPlease insert your number of hours worked: ");
    float hour;
    scanf("%f", &hour);

    float gross;
    if (hour<=40)
    {
        gross=hour*hourrate;
    }
    else
    {
        gross=40*hourrate+(hour-40)*hourrate*0.5;
    }

    float net = gross-(gross*3.625/100);
    float averagepay=net/7;
    printf("\n%d:\n", id);
    printf("\toverall total net pay: %.2f\n", net);
    printf("\taverage net pay: %.2f\n", averagepay);
    getchar();
    return 0;
}

Please, clarify better your issue.

[teopeishen]

i run the program. the program cannot run more than three lines of command. until

printf("\t Please insert your hourly wage rate:");

[teopeishen]

i think i found the problem.
i put .2f in the scanf("%.2f",hourrate). That is the problem. After omit it, it seems fine.