scanf , printf

[zeroblank]

the reference says the %s should be a string type arguement but when i implemented it the compilers gave me a warning that's a char and it really only reads chars

  	string x;
	scanf("%s",&x);
	printf("%s",&x);

any thoughts ?

[Chervil]

string x is C++
scanf/printf are C

First decide which language you are using, and then be consistent.

However, since this is a C++site, how about

    string x;
    cin >> x;
    cout << x;

[zeroblank]

oh .. then why it's in the cplusplus reference ?

[zeroblank]

The reason im using scanf is that it omit spaces so basically it saves me some time of coding

[Thomas1965]

oh .. then why it's in the cplusplus reference ?

C is still part of C++ that's probably the reason.

If you really need to use scanf and a string, here's a way to do it:

#include <iostream>
#include <string>
#include <cstdio>

int main()
{
  // Just a proof of concept - not really advisable to do

  std::string buffer(10, ' ');
  printf("Your input: ");
  scanf("%9s", &buffer[0]);
  printf("\n%s", buffer.c_str());

  system("pause");
  return 0;
}

[zeroblank]

C is still part of C++ that's probably the reason.  

so where did i go wrong , i must have missed something :\ .. why %s reads only a char ?

[Thomas1965]

Have a look at the post above yours - probably you didn't see my edit.

[zeroblank]

Cool so basically %9s iterate over the string which is basically an array of chars .. thanks was a big deal of help ^^