Exception throw error
Exception thrown at 0x0F7D40DA
this code works fine,first matrix 3x3 and second matrix 3x2 it give expection error at second matrix when i give some values to it
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#include<iostream>
using namespace std;
int main()
{
int row, col, row1, col1, store, temp, **arr, **arr1, **arr2 = NULL;
row = col = row1 = col1 = store = temp = 0;
cout << "\nFirst Matrix\n";
cout << "\nEnter The Row : ";
cin >> row;
cout << "\nEnter The Col : ";
cin >> col;
cout << "\nSecond Matrix\n";
cout << "\nEnter The Row : ";
cin >> row1;
cout << "\nEnter The Col : ";
cin >> col1;
if ((col == row1))
{
arr = new int*[row];
arr1 = new int*[row1];
arr2 = new int*[row];
for (int i = 0; i < col; i++)
arr[i] = new int[col];
for (int i = 0; i < col1; i++)
arr1[i] = new int[col1];
for (int i = 0; i < col1; i++)
arr2[i] = new int[col1];
// error first matrix 3x3 and second 3x2
cout << "\nFirst Matrix input\n";
for (int i = 0; i < row; i++)
{
for (int j = 0; j < col; j++)
{
cin >> arr[i][j];
}
}
cout << "\nSecond Matrix input\n";
for (int i = 0; i < row1; i++)
{
for (int j = 0; j < col1; j++)
{
cin >> arr1[i][j]; // getting expection error at this line
}
}
for (int i = 0; i < row; i++)
{
for (int j = 0; j < col1; j++)
{
store = (arr[i][j] * arr1[j][temp]) + store;
if (temp == col1)
break;
else if (j == col1 - 1)
{
arr2[i][temp] = store;
temp++;
store = 0;
j = -1;
}
else
continue;
}
temp = 0;
store = 0;
}
}
else
{
cout << "\nProduct Of these matrices are undefined\n";
}
if (arr2 == NULL)
return;
else
{
cout << "\nProduct Of These Two Matrices\n";
for (int i = 0; i < row; i++)
{
for (int j = 0; j < col1; j++)
{
cout << arr2[i][j] << " ";
}
cout << endl;
}
}
}
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error pic
http://oi65.tinypic.com/1zn6eqo.jpg
Last edited on
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arr = new int*[row];
for (int i = 0; i < col; i++)
arr[i] = new int[col];
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you allocate `row' elements, but you traverse `col' cells.
Last edited on
Sorry i did not get you what are you trying to say
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arr = new int*[row];
for (int i = 0; i < col; i++)
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do a desk check.
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