Descending order of integers

[hstrauss]

So right now, when I run this with an integer of 25, it spits out 1, 5, 25. I need it to be reversed like 25, 5, 1. Please help!!


#include <iostream>
#include <cmath>
#include <iomanip>

using namespace std;

int main()
{
int i = 0;
int integer = 0;
cin >> integer;


for ( i = 1; i <= integer; i++ )
{
if (integer % i == 0)
cout << i << endl;
}


system("pause");
return 0;

}

[jonnin]

you can do almost anything in a for loop.

such as
for( i = 25; i >0; i /=5;)
cout << i << endl;

you are not confined to ++ and --, you can put any legal expression in there.


Here you can just reverse the loop,
i = integer, i >= 0, i-- if I did that right.

[hstrauss]

Hmm...I tried that last one and it gave me a runtime error

[integralfx]

Simply change the starting condition of the for loop to integer and decrement instead of incrementing.

for ( int i = integer; i > 0; i-- )
{
    if( integer % i == 0 )
        cout << i << '\n';
}

[jonnin]

sorry! I triggered divide by zero with my lack of attention to details!

[hstrauss]

Thanks integralfx!! it worked!